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3 years ago

Does the mass of an object dictate the acceleration of a falling object

Physics

2 answers:

daser333 [38]3 years ago

7 0

Answer: no

The acceleration of an object is equivalent to the gravitational acceleration. The size, shape, and weight of an item are not a cause in the motion of the object. So all objects, regardless of its mass, size, or shape fall freely with the same acceleration.

muminat3 years ago

5 0

Answer:

No.

Explanation:

Because the acceleration of falling objects is constant and is not affected by mass

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A solenoidal coil with 21 turns of wire is wound tightly around another coil with 350 turns. The inner solenoid is 22.0 cm long

Thepotemich [5.8K]

Answer:

(a)The average of magnetic flux trough each turns is $3.63 \times 10^{-8}$ wb.

(b) The magnitude of mutual inductance of the two solenoid is $1.596 \times 10^{-5}$ H.

(c)The magnitude of emf induced in the outer solenoid by changing current in the inner solenoid is 0.027132 v .

Explanation:

Given that,

The number of turns of the solenoid=N₁= 350

The diameter of the solenoid=D= 2.20 cm=0.022

The length of the solenoid is = $l$ = 22.0 cm=0.22 m

The second solenoid with $N_2$ = 21 turns which is wound around the solenoid at its center.

The current in the inner solenoid is $I_1$ = 0.150 A and is increasing at a rate of 1700 A/s i.e $\frac{dI_1}{dt}= 1700$ A/s

(a)

The formula of magnetic field of a solenoid is

$B=\mu_0 nI=\frac{\mu_0 N_1I_1}{l}$

$=\frac{(4\pi \times 10^{-7} T.m/A) (350)(0.15 \ A)}{0.220 \ m}$

$\approx 3.0 \times 10^{-4}$ T

So, the magnetic flux of each turns

$\phi = BA=B \pi (\frac d2)^2$

$=(3.0\times 10^{-4}\ T)\pi (\frac {0.022}{2} \ m)^2$

$=1.14 \times 10^{-7}$ wb

The average of magnetic flux trough each turns is $3.63 \times 10^{-8}$ wb.

(b)

Since the both coil wound tightly. So, the magnitude magnetic flux though each turns of both coils is same.

The mutual inductance of the two solenoid is

$M=\frac{N_2\phi}{I_1}$

$=\frac{(21)(1.14 \times 10^{-7}\ wb)}{0.15\ A}$

$=1.596 \times 10^{-5}$ H

(c)

The formula of emf is

$\varepsilon =-M\frac{dI_1}{dt}$

$=-(1.596\times 10^{-5}\ H) (1700 \ A/s)$

$=27.132 \times 10^{-3}$ v

=0.027132 v

The emf induced in the outer solenoid by changing current in the inner solenoid is 0.027132 v .

4 0

3 years ago

Find a numerical value for ρearth, the average density of the earth in kilograms per cubic meter. use 6378km for the radius of t

Andre45 [30]

Answer:

5501 kg/m^3

Explanation:

The value of g at the Earth's surface is

$g=\frac{GM}{R^2}=9.70 m/s^2$

where G is the gravitational constant

M is the Earth's mass

$R=6378km = 6.378 \cdot 10^6 m$ is the Earth's radius

Solving the formula for M, we find the value of the Earth's mass:

$M=\frac{gR^2}{G}=\frac{(9.81 m/s^2)(6.378\cdot 10^6 m)^2}{6.67\cdot 10^{-11}}=5.98\cdot 10^{24}kg$

The Earth's volume is (approximating the Earth to a perfect sphere)

$V=\frac{4}{3}\pi r^3 = \frac{4}{3}\pi (6.378\cdot 10^6 m)^3=1.087\cdot 10^{21} m^3$

So, the average density of the Earth is

$\rho = \frac{M}{V}=\frac{5.98\cdot 10^{24} kg}{1.087\cdot 10^{21} m^3}=5501 kg/m^3$

4 0

4 years ago

Read 2 more answers

A body of mass 10kg has a height of 200cm, calculate the potential energy. (Take g =

Nastasia [14]

The potential energy of the body is "200 Joule".

According to the question,

Mass,

m = 10 kg

Height,

h = 200 cm

or,

= 2 m

g = 10 m/s⁻¹

As we know,

→ The potential energy will be:

= $mgh$

By putting the given values, we get

= $10\times 10\times 2$

= $200 \ Joule$

Thus the above answer is right.

Learn more about potential energy here:

brainly.com/question/23859978

5 0

3 years ago

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In what direction do seismic waves carry the energy of an earthquake? a. away from the focus b. toward the focus c. from the sur

luda_lava [24]

When an earthquake strikes usually seismic waves carry the energy outward (a.) With the greatest power at the focus and as the seismic waves travel outward they become more and more weak until they disappear.<span />

6 0

3 years ago

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A proton has a speed of 3.50 Ã 105 m/s when at a point where the potential is +100 V. Later, itâs at a point where the potential

ruslelena [56]

Answer:

(a). The change in the protons electric potential is 0.639 kV.

(b). The change in the potential energy of the proton is $1.022\times10^{-16}\ J$