Answer:
Coefficient of friction.
Explanation:
The amount of friction divided by the weight of an object is equal to the coefficient of friction. It is a dimensional less number. It can be given by :
N is normal force.
= coefficient of friction
Answer with Explanation:
a. Option d is true.
a negatively charged plane parallel to the end faces of the cylinder
b. Radius of cylinder, r=0.66m
Magnitude of electric field, E=300 N/C
We have to find the net flux through the closed surface.
Net electric flux,
c.
Net charge,
Where
Where
a)You throw a stone horizontally at a speed of 5.0 m/s from the top of a cliff that is 78.4 m high.
from above statement we got
height = 78.4 m
since the ball is thrown, so its vertical velocity would be zero
u = 0
taking g = 9.8m/s^2
now, using the equation of motion
h = ut + gt^2/2
now putting all the values in it
we got ,
78.4 = 9.8 * t^2/ 2
by solving we got,
t = 4 sec
b) now, since along the horizontal , no force acting and accelaration is zero so
R = ut , R is RANGE
R = 5 * 4
range = 20 m
c) vertical components of the stone’s velocity just before it hits the ground = v sin θ =
horizontal components of the stone’s velocity just before it hits the ground = v cos θ
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Answer:
y (t) = 0.754 * cos ( 7.96 t - 69.52)
Explanation:
Given:
m = 1.5 kg , k = 95 N / m , v₀ = 6 m / s , d = 0.35 m , t = 0
y (t) = A * cos ( ω * t - φ )
Using the equation that describe the motion
m * v = - k * x ⇒ m * x'' = - k * x
Angular velocity is equal to
ω = √ k / m ⇒ ω = √ 95 N /m / 1.5 kg
ω = 7.96 rad /s
A = v / ω ⇒ A = 6 m /s / 7.96 rad / s
A = 0.754
d = cos * φ ⇒ φ = cos ⁻¹ * 0.35
φ = 69.52
y (t) = A * cos ( ω * t - φ ) ⇒ y (t) = 0.754 * cos ( 7.96 t - 69.52)