1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Romashka-Z-Leto [24]
3 years ago
8

CAN YOU EXPLAIN?How do static charges interact and how are they released​

Chemistry
1 answer:
taurus [48]3 years ago
5 0
Static electricity is the result of an imbalance between negative and positive charges in an object. These charges can build up on the surface of an object until they find a way to be released or discharged. ... The rubbing of certain materials against one another can transfer negative charges, or electrons.
You might be interested in
i'm reasking this, i need help with this and it's due today. the answer isn't 30,240 minutes, it's the blanks i need filled in :
adelina 88 [10]

Answer:

Explanation:

24hours ×21 days=

you will get the answeer

3 0
3 years ago
A popular car has a gas tank that holds a maximum of 14.5 gallons of fuel. What is
gulaghasi [49]

Taking into account the change of units, the size of the tank is 54.88 liters.

In first place, the rule of three is a tool used to quickly solve problems involving a proportional relationship between two variables.

The rule of three is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them.

If the relationship between the magnitudes is direct, that is, when one magnitude increases, so does the other (or when one magnitude decreases, so does the other), the direct rule of three should be applied.

The rule of three is applied as follows, with A, B and C being known values ​​and D being an unknown value: if A maintains a certain relationship with B, and it is known that C and D have the same relationship, it is possible to calculate the unknown value D using the following expression:

D=\frac{CxB}{A}

In this case, the rule of three can be applied as follows: if 1 gallon is equal to 3.785 liters, 14.5 gallons are equal to how many liters?

D=\frac{14.5 gallonsx3.785 liters}{1 gallon}

Solving:

D= 54.88 liters

In summary, the size of the tank is 54.88 liters.

Learn more with this example:

  • <u>brainly.com/question/17839792?referrer=searchResults</u>
  • <u>brainly.com/question/14586541?referrer=searchResults</u>

7 0
2 years ago
Read 2 more answers
What is the name for the formula C5O10?
Natalija [7]

Propylethylene would be the answer

8 0
3 years ago
Read 2 more answers
For any molecule at the surface the resulting surrounding forces equal zero
Katarina [22]
False is the correct answer
4 0
3 years ago
Read 2 more answers
If 1.85 g of Mg(OH)2 reacts with 3.71 g of HCl,
Damm [24]
Both of them are a hope this helps
8 0
3 years ago
Other questions:
  • Can someone plz help me with Visualize it! 5 plz I will mark them Brainliest
    12·1 answer
  • You cannot round a number if it has a decimal point true or false
    14·1 answer
  • Which element has the electron configuration [Xe] 6s2 4f14 5d10 6p2?
    9·1 answer
  • An aluminum can weighing 10 g absorbs 106.8 J of heat and warms by 12 degrees C. What is the specific heat of the aluminum can?
    14·1 answer
  • When 91.5 g of isopropyl alcohol which has an empirical formula of C3H8O is burned in excess oxygen gas, how many grams of H2O a
    10·1 answer
  • Si escuchas a alguien decir que la corriente eléctrica en un sircuito sale por el polo negativo de la pila y entra por el polo p
    10·1 answer
  • How many molecules are in 228.7 grams of KBr?
    15·1 answer
  • Explain the structure of an atom. Make sure to include the charges of the subatomic particles.
    10·1 answer
  • Please help me I’m desperate plz help and fast
    10·1 answer
  • How do you find the core electrons of the elements in the periodic table?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!