The concentration of the HI solution is 0.75M.
<h3>How do we calculate the required concentration?</h3>
Required concentration of any solution used in titration will be calculated by using the below equation as:
M₁V₁ = M₂V₂, where
M₁ & V₁ are the molarity and volume of CsOH.
M₂ & V₂ are the molarity and volume of HI.
On putting all values from the question, we get
M₂ = (1.9)(9.9) / (25) = 0.75M
Hence required concentration of HI solution is 0.75M.
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Answer:
1.3 M
Explanation:
The question asks to calculate the molarity of a solution.
We have to use the following equitation:
Molarity = # moles / 1 lt of solution
In this case we have a solution composed of 0.65 mol of NaF diluted in a total volume of 0.5 lt. We will have to do the following cross multiplication solving for x:
0.65 mol NaF / 0.5 lt = x mol NaF/ 1 lt
x = 1.3 mol NaF / 1 lt = 1.3 M
Answer:
<u>Oxygen</u>
Explanation:
If we had the same question then the table would've given the specific heat for these gases:
Water (steam) | 2.08
Air (25°C) | 1.01
Oxygen | 0.92
Hydrogen | 14.30
Out of these options, oxygen has the lowest specific heat and so it has the least heat-storing ability of the group.
Answer: 67.23 L
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 
of particles.
To calculate the number of moles, we use the equation:
Putting in the values we get:
1 mole of methane occupies = 22.4 L
Thus 3 moles of methane occupy = 
Thus volume of 48 grams of methane gas is 67.23 L
