Answer:
276g
Explanation:you are adding salt to water the mass is not destroyed so you just add the numbers hope this helps god bless
That is phosphorus trichloride and a COVALENT BOND
Cl needs one electron and P has metallic character, it donates electron easy
Answer:
7.4 - 5.4.
Explanation:
The relationship between HIn that is the non-ionized form and the In^-; the ionized form is an equilibrium Reaction which is given below;
HIn(aq) + H2O(l) <--------> H3O^+(aq). + In^-(aq).
From the question, we are given that the ka is 4 ×10^−7, therefore, the mathematical relationship between HIn and In^- is given below;
Ka = [H3O^+] [In^-] / [HIn] = 4 ×10^−7.
The formula we are going to be using to solve this question is given below;
pH = pKa (+ or -) 1.
Recall that the relationship between the ka and pKa;
pKa = - log (ka).
pKa = - log ( 4 ×10^−7).
pKa = 6.4
Therefore, for it to have a distinct color change, the pH range will be;
pH = pKa (+ or -) 1.
pH= 6.4 + 1 = 7.4.
pH= 6.4 - 1 = 5.4.
Hence, the pH range = 7.4 - 5.4.
I'm not sure but it should be 7.31 times 2 times 3.14 or pi
7.31 x 2 x 3.14 = 45.9068
If you need to round to the nearest tenth it will be 45.9
If you need to round to the nearest hundredth it will be 45.91
3.16 X 10^-11 M is the [OH-] concentration when H3O+ = 1.40 *10^-4 M.
Explanation:
data given:
H30+= 1.40 X 10^-4 M\
Henderson Hasslebalch equation to calculate pH=
pH = -log10(H30+)
putting the values in the equation:
pH = -log 10(1.40 X 10^-4 M)
pH = 3.85
pH + pOH =14
pOH = 14 - 3.85
pOH = 10.15
The OH- concentration from the pOH by the equation:
pOH = -log10[OH-]
10.5= -log10[OH-]
[OH-] = 10^-10.5
[OH-] = 3.16 X 10^-11 is the concentration of OH ions when hydronium ion concentration is 1.40 *10^-4 M.
