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Ghella [55]
3 years ago
7

The balanced chemical equation for the reaction of copper (Cu) and silver nitrate (AgNO3) is shown below. Cu + 2AgNO3 mc001-1.jp

g 2Ag + Cu(NO3)2 How many moles of copper must react to form 3.50 mol of Ag?
Chemistry
2 answers:
sergij07 [2.7K]3 years ago
8 0
The balanced reaction is:

<span>Cu + 2AgNO3 = 2Ag + Cu(NO3)2

We are givent the amount of silver to be produced. This will be the starting point. Calculations are as follows:

</span><span> 3.50 mol Ag ( 1 mol Cu / 2 mol Ag ) = 1.75 mol Cu
</span>
Therefore, we need 1.75 mol of copper in order to produce 3.50 mol of silver.
nirvana33 [79]3 years ago
5 0

Answer:

1.75 moles of copper must react to form 3.50 mol of Ag.

Explanation:

Cu + 2AgNO_3\rightarrow 2Ag + Cu(NO_3)_2

According to reaction 2 moles of silver are obtained from 1 mole of copper.

Then 3.50 mole of Silver will be obtained from:

\frac{1}{2}\times 3.5 mol=1.75 mol

1.75 moles of copper must react to form 3.50 mol of Ag.

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3 years ago
A solution of acetic acid has a pH of 3.45. What is the concentration of acetic acid in this solution? Ka for CH3COOH is 1.8×10-
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Answer:

0.007 M

Explanation:

pH is defined as the negative logarithm of the concentration of hydrogen ions.

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Where, C is the concentration = ?

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3 years ago
What are deltaTb and deltaTf for an aqueous solution that is 1.5g nacl in 0.250kg h2o? Given Kb=0.51 C/m and kr=1.86 C/m
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Answer:

T_f for given question is 2.79 and T_b is 0.52

\Delta T_b = I \times K_b \times m {i- vant hoff’s constant ; Kb- constant ; m molarity }

M = no. of moles of the solute present in one kg of solution

Let the weight of amount of solute be “w” and its molecular mass be “M”

Let the mass of the solvent in the given question be “x”

\Delta T_b = I \times K_b \times (w/M)/ x

\Delta T_b = I \times K_b \times w/Mx

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\Delta T_f = M \times K_f = 1.86 \times 1.5 = 2.79

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3 years ago
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