Answer:
Explanation:
In one mole of liquid HF , no of molecules is 6.02 x 10²³.
Each molecule forms two hydrogen bonds on an average so no of hydrogen bonds per mol ih HF is
2 x 6.02 x 10²³.
= 12.04 x 10²³ .
In water no of hydrogen bonds per molecule of water is 4 . So in one mole of water no of hydrogen bonds is
4 x 6.02 x 10²³.
= 24.08 x 10²³ .
Answer:
Increasing precision with multiple measurements
Explanation:
The more measurements you take (provided there is no problem with the clock!), the better your estimate will be. Taking multiple measurements also allows you to better estimate the uncertainty in your measurements by checking how reproducible the measurements are.
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From the calculations and the statement of the general gas equation, the volume of the gas becomes 28.8 L
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What are gas laws?</h3>
The gas laws are used to show the relationship between the variables in problems that has to do with gases.
In this case, we have to apply the general gas law as follows;
P1V1/T1 = P2V2/T2
P1V1T2 = P2V2T1
V2 = * 22L * 1.5 atm * 273K/313K * 1 atm
V2 = 28.8 L
Learn more about gas laws:brainly.com/question/12667831
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Answer:
17,932.69 g/mol is the molecular weight of the substance.
Explanation:
Using Beer-Lambert's law :
Formula used :
where,
A = absorbance of solution = 1.04
c = concentration of solution =?
l = length of the cell = 1 cm
= molar absorptivity of this solution = 18,650 
Now put all the given values in the above formula, we get the molar absorptivity of this solution.
c = 

V = Volume of the solution in L
Molecular weight of the substance = x
V = 100 mL = 0.1 L
Mass of the substance = 100 mg = 0.1 g

x = 17,932.69 g/mol
17,932.69 g/mol is the molecular weight of the substance.
The law of conservation of mass states that mass can neither be created nor destroyed. For example in an isolated system, mass of the reactants is equal to the mass of the products. Thus, mass or the quantity of the system under consideration will remain unchanged through any physical or chemical process.
In the given example, the board initially has a mass of 750 g. It is physical transformed to sawdust by grinding. Based on the conservation of mass, the pile of sawdust would still weigh 750 g.