The wt% of KOH = 45%
This implies that there is 45 g of KOH in 100 g of the solution
Density of the solution is given as 1.45 g/ml
Therefore, the volume corresponding to 100 g of the solution is
= 100 g * 1 ml /1.45 g = 68.97 ml = 0.069 L
Now concentration of the concentrated KOH solution is:
Molarity = moles of KOH/vol of solution
= (45 g/56.105 g.mol-1)/0.069 L = 11.6 M
Thus,
Initial KOH concentration M1 = 11.6 M
Initial volume = V1
Final concentration M2 = 1.20 M
Final volume V2 = 250 ml
M1*V1= M2*V2
V1 = M2*V2/M1 = 1.20*250/11.6 = 25.9 ml = 26 ml
Answer:
Here we need to find the morality of 60 grams of NaOH dissolved in 750ml because the amount of solute is usually taken in ml and 750 litres is way to high.
So, coming towards the question, we need to find molarity.
As we know, molarity is no of moles of a substance per litre of the solution.
Molarity= mole\volume ----> 1
Now we will change 750ml to litres
750/1000 = 0.75 litres
Now we need to find no of moles of NaOH.
As we know, no of moles = mass /molar mass
no of moles =60 grams / 40
no of moles= 1.5 moles
Putting the values of no of moles and volume in equation 1
Molarity= mole\volume ----> 1
=1.5 moles/ 0.75 litres
=2 M
So the answer will be 2 Molar.
Sorry but it depends on the gas in question and it's temperature of condensing /boiling point if this it 0° it will turn liquid
Answer:
a. The electron is a standing wave that can only have an integer number of wavelengths.
Explanation:
As per quantum physics, the theory of wave-particle duality refers to the notion that matter and light show the characteristics of both waves and particles, based on the case of the experiment. Much like light, the matter appeared to possess both wave and particle properties. Large objects display very low wavelengths, but for small particles, the wavelength may be detected and important, as shown by a double-slit experiment with electrons.