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Arada [10]
3 years ago
14

Which branch of chemistry specifically deals with quantitative analysis?

Chemistry
2 answers:
Nina [5.8K]3 years ago
6 0

Answer: Analytical chemistry

Explanation:I just finished this question

LUCKY_DIMON [66]3 years ago
4 0

Answer:

analyitical

Explanation:

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In the name, iron(III) oxide, the (III) represents
Veronika [31]
<h2>In the name, iron(III) oxide, the (III) represents: D) the electrical charge of iron</h2><h2>Explanation:</h2>

To attain stability the chemical bond is formed .

Chemical bond

It is a kind of linkage that binds one atom with the other .

The atoms do so in order to attain stable noble gas configuration .

To form chemical bond they either:

Loose electrons : when atoms loose electrons they acquire positive charge which is equal to the number of electrons lost .

Gain electrons: After gaining electrons they acquire negative charge which is equal to the number of electrons gained by an atom.

share electrons : With sharing no charges are develop .

<em>In the above asked question when iron combines with oxygen it forms iron oxide : where iron looses 3 electrons and oxygen gains 2 electrons .That is the reason ,III here represents  the electrical charge of iron</em>

7 0
3 years ago
Jason measures three values of density for his unknown. The values he obtains are: 1.019 g/mL 1.498 g/mL 1.572 g/mL What is the
jok3333 [9.3K]

<u>Answer:</u> The average of the densities of the given measurements is 1.363 g/mL

<u>Explanation:</u>

The equation used to calculate density of a substance is given by:

\text{Density of a substance}=\frac{\text{Mass of a substance}}{\text{Volume of a substance}}

We are given:

First measured value of density, d_1 = 1.019 g/mL

Second measured value of density, d_2 = 1.498 g/mL

Third measured value of density, d_3 = 1.572 g/mL

Putting values in above equation, we get:

\rho_{mix}=\frac{d_1+d_2+d_3}{3}

\rho=\frac{1.019+1.498+1.572}{3}\\\\\rho=1.363g/mL

Hence, the average of the densities of the given measurements is 1.363 g/mL

7 0
3 years ago
11.
andrew11 [14]
B. Groups (families)
6 0
3 years ago
Complete each statement to identify the form of asexual reproduction.
Mrrafil [7]

Spore formation is a form of asexual reproduction used by mushrooms and molds.

During  budding, the offspring grows from the body of the parent.

Fragmentation is a form of asexual reproduction that must be followed by regeneration.

Explanation:

Asexual reproduction is the type of reproduction where the gamete formation and fusion have no relevance or existence. It functions on the process of somatic cell division via mitosis and the offsprings are identical to their parents.

The spore formation occurs in fungi through sporangia, bursting open to shed spores, forming into a new young ones. Budding occurs out as an outgrowth of the parent and attains maturity and separates. Fragmentation is the process where the parents fall apart into pieces and regeneration follows.

8 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP Nuclear power plants real ease energy by
sweet [91]
Nuclear power plants real ease energy by FISSION

(this is the process when a heavy, unstable atomic nucleus splits into 2 or more lighter elements. This process releases lots of energy.)

I hope this helped you out! :)
3 0
3 years ago
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