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balu736 [363]
3 years ago
7

HELP ASAP ILL GIVE BRAINLIEST!!

Chemistry
1 answer:
Dahasolnce [82]3 years ago
3 0

Of course we would experience them.

You might be interested in
Be sure to answer all parts. The sulfate ion can be represented with four S―O bonds or with two S―O and two S═O bonds. (a) Which
VMariaS [17]

Answer:

a) Representation - (in attachment)

b) Tetrahedral geometry and

c) sp^{3} hybrid orbitals invovle sigma bonding.

\pi orbitals are formed by the overlapping of d-orbitals of sulfur with p-orbitals of oxygen.

Explanation:

a)

Representation in attachment.

The overall charge in the both structures are -2. The structure (b) is favored by the resonance structures since the formal charge with in the species are remained.

Therefore, structure (b) is the better representation of sulfate ion.

b)

In sulfate ion, sulfur atom is attached with four different oxygen atoms. According to the VSEPR theory , the sufate ion has tetrahedral geometry.

There is four sigma bonds and zero lone pairs present on the central metal atom.

Hence, the hybridization of the sulfur atom is sp^{3}

c)

The s and p orbitals of sulfur invovles hybridization and form sigma bonds.The orbitals of sulfur involves \pi bonding.

Therefore, \pi bonds are formed by the overlapping of d-orbitals of sulfur with  p-orbitals of oxygen.

5 0
4 years ago
If I leave 750 mL of a 0.40 M sodium chloride solution uncovered on a windowsill
mel-nik [20]

Answer:

B. 0.5 molar

Explanation:

Given data:

Initial concentration = 0.40 M

Initial volume = 750 mL

Final volume =750  -  150 mL = 600 mL

Final concentration = ?

Solution:

Molarity is the number of moles of solutes in litter of solvent. In given problem it is stated that when the solution is uncovered solvent evaporate it means molarity is changed. we can calculate the new molarity with the following formula.

C₁V₁ = C₂V₂

C₁ = initial concentration

V₁ = initial volume

C₂ = final concentration

V₂ = final volume

Now we will put the values in formula.

C₁V₁ = C₂V₂

0.40 M × 750 mL = C₂ × 600 mL

300 M.mL / 600 mL = C₂

0.5 M = C₂

5 0
3 years ago
What is name of HOPBr2 ?
USPshnik [31]
HOPBr₂ = <span>dibromophosphinous acid

hope this helps!

</span>
5 0
3 years ago
Give the complete ionic equation for the reaction (if any) that occurs when aqueous solutions of lithium sulfide and copper (II)
Aloiza [94]

Answer:

2Li^+_{(aq)}+S^{2-}_{(aq)}+Cu^{2+}_{(aq)}+2NO_3^{-}_{(aq)}\rightarrow CuS_{(s)}+2Li^+_{(aq)}+2NO_3^{-}_{(aq)}

Explanation:

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

The balanced molecular equation will be,

Li_2S_{(aq)}+Cu(NO_3)_2_{(aq)}\rightarrow CuS_{(s)}+2LiNO_3_{(aq)}

The complete ionic equation in separated aqueous solution will be,

2Li^+_{(aq)}+S^{2-}_{(aq)}+Cu^{2+}_{(aq)}+2NO_3^{-}_{(aq)}\rightarrow CuS_{(s)}+2Li^+_{(aq)}+2NO_3^{-}_{(aq)}

4 0
3 years ago
Calculate the mass percent 250g of salt solution that has 3.50g salt residue
Anna35 [415]

Answer:

1.4% salt residue

Explanation:

Mass percent can be found using the formula:

mass of solute (grams)
------------------------------------  x 100%
mass of solution (grams)

Therefore, since you have been given the weights of both the solute and solution, you can use the formula to solve for the mass percent.

3.50 g salt residue
-----------------------------  =  0.014 x 100%  = 1.4% salt residue
250 g salt solution

8 0
2 years ago
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