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Ronch [10]
3 years ago
12

Velocity v (m/s)

Physics
1 answer:
Sonja [21]3 years ago
3 0

Explanation:

given solution

h=45m v^2=u^2+2gh

g=10m/s^2 v^2=0^2+2×10m/s^2×45m

vi=0 v^2=900m^2/s^2

  • v=30
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I WILLLL GIVEEEEEE YOU BRAINLYYYYY!!!!!!!!!! Write your own definition of Scientific Law and a Scientific Theory in your own wor
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Explanation:

scientific laws are totally fixed.

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3 years ago
You have designed and constructed a solenoid to produce a magnetic field equal in magnitude to that of the Earth (5.0 10-5 T). I
saul85 [17]

Answer:

I = 0.03637 A

Explanation:

The given data in the question is

Magnetic field : B = 5.0 \times 10^{-5} T

Turns : N = 350

Length : L = 32 cm = 0.32 m

So, number of turns per unit length :

n=\frac{N}{L}

n=\frac{350\: turns}{0.32 m}

n=1093.75 \: turns \: per \: meter

If current is I , then magnetic field is given by

B = \mu_{0} \times n \times I

Also,

I = \frac{B}{\mu_{0} \times n}

Insert the values

I = \frac{5.0 \times 10^{-5}}{4 \pi \times 10^{-7} \times 1093.75} A

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5 0
4 years ago
Which is a property that mendeleev predicted for gallium
seropon [69]
A; Metal This is because of maths
8 0
4 years ago
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A sample of copper with a mass of 1.80 kg, initially at a temperature of 150.0°C, is in a well-insulated container. Water at a t
user100 [1]

Answer:

the mass of water is 0.3 Kg

Explanation:

since the container is well-insulated, the heat released by the copper is absorbed by the water , therefore:

Q water + Q copper = Q surroundings =0 (insulated)

Q water = - Q copper

since Q = m * c * ( T eq - Ti ) , where m = mass, c = specific heat, T eq = equilibrium temperature and Ti = initial temperature

and denoting w as water and co as copper :

m w * c w * (T eq - Tiw) = - m co * c co * (T eq - Ti co) =  m co * c co * (T co - Ti eq)

m w = m co * c co * (T co - Ti eq) / [ c w * (T eq - Tiw) ]

We take the specific heat of water as c= 1 cal/g °C = 4.186 J/g °C . Also the specific heat of copper can be found in tables → at 25°C c co = 0.385 J/g°C

if we assume that both specific heats do not change during the process (or the change is insignificant)

m w = m co * c co * (T eq - Ti co) / [ c w * (T eq - Tiw) ]

m w= 1.80 kg *  0.385 J/g°C ( 150°C - 70°C) /( 4.186 J/g°C ( 70°C- 27°C))

m w= 0.3 kg

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4 years ago
Which of the following is not a physical change?
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C because of galvination is sized
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