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Ronch [10]
2 years ago
12

Velocity v (m/s)

Physics
1 answer:
Sonja [21]2 years ago
3 0

Explanation:

given solution

h=45m v^2=u^2+2gh

g=10m/s^2 v^2=0^2+2×10m/s^2×45m

vi=0 v^2=900m^2/s^2

  • v=30
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A ticker timer 50dots per second. When a body is pulled by a tap through the timer, the distance between the third and fourth do
Amiraneli [1.4K]

Answer:

Explanation:

Time for one dot = 1 /50 = .02 s

Distance between 3 rd and fourth dot is 3 cm and time taken to travel this distance is .02 s

velocity = 3 cm / .02 = 150 cm /s

Distance between 4 th and 5 th  dot is 4 cm and time taken to travel this distance is .02 s

velocity = 4 cm / .02 = 200 cm /s

change in velocity = 200 cm/s  - 150cm/s = 50 cm /s

Time taken = .02 s

Acceleration = 50 / .02 cm/s²

= 2500 cm/s²

6 0
3 years ago
What is the electron dot diagram for magnesium oxide?
timofeeve [1]

Answer:

The electron dot diagram for magnesium oxide consists of magnesium in Mg2+form, and oxygen showed with 8 valence electrons (dots) with a negative charge of 2.

3 0
2 years ago
Read 2 more answers
When you take your 1900-kg car out for a spin, you go around a corner of radius 53m with a speed of 13m/s. The coefficient of st
anastassius [24]

Answer:

Ff = 6058.5N

Explanation:

The sum of forces is:

Ff = m*a_c

Ff = m*V^2/R

Ff = 1900*13^2/53

Ff = 6058.5N

3 0
3 years ago
A 200-Ω resistor is connected in series with a 10-µF capacitor and a 60-Hz, 120-V (rms) line voltage. If electrical energy costs
Vika [28.1K]

Answer:

Cost to leave this circuit connected for 24 hours is $ 3.12.

Explanation:

We know that,

\mathrm{X}_{\mathrm{c}}=\frac{1}{2 \pi \mathrm{fc}}

f = frequency (60 Hz)

c= capacitor (10 µF = 10^-6)  

\mathrm{X}_{\mathrm{c}}=\text { Capacitive reactance }

Substitute the given values

\mathrm{X}_{\mathrm{c}}=\frac{1}{2 \times 3.14 \times 10 \times 10^{-6} \times 60}

\mathrm{X}_{\mathrm{c}}=\frac{1}{3.768 \times 10^{-3}}

\mathrm{x}_{\mathrm{c}}=265.39 \Omega

Given that, R = 200 Ω

X^{2}=R^{2}+X c^{2}

X^{2}=200^{2}+265.39^{2}

X^{2}=40000+70431.85

X^{2}=110431.825

x=\sqrt{110431.825}

X = 332.31 Ω

\text { Current }(I)=\frac{V}{R}

\text { Current }(I)=\frac{120}{332.31}

Current (I) = 0.361 amps

“Real power” is only consumed in the resistor,  

\mathrm{I}^{2} \mathrm{R}=0.361^{2} \times 200

\mathrm{I}^{2} \mathrm{R}=0.1303 \times 200

\mathrm{I}^{2} \mathrm{R}=26.06 \mathrm{Watts} \sim 26 \mathrm{watts}

In one hour 26 watt hours are used.

Energy used in 54 hours = 26 × 24 = 624 watt hours

E = 0.624 kilowatt hours

Cost = (5)(0.624) = 3.12  

3 0
2 years ago
If it takes a ball dropped from rest 2.069 s to fall to the ground, from what height h was it released?
Ganezh [65]
I dont know the answer im sorry
6 0
3 years ago
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