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Ronch [10]
2 years ago
12

Velocity v (m/s)

Physics
1 answer:
Sonja [21]2 years ago
3 0

Explanation:

given solution

h=45m v^2=u^2+2gh

g=10m/s^2 v^2=0^2+2×10m/s^2×45m

vi=0 v^2=900m^2/s^2

  • v=30
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Roman citizenship guaranteed Paul:
deff fn [24]
<span>protection from injustices</span>
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3 years ago
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If a 2 x 10^-4C test charge is given 6.5J of energy, determine the electric potential difference.
Gwar [14]

Answer:

The electric potential difference is 32500 volt.

Explanation:

Given that,

Chargeq=2\times10^{-4}C

Energy = 6.5 J

We need to calculate the electric potential difference

Potential difference :

Potential difference is equal to the energy divide by charge.

Using formula of potential difference

V=\dfrac{E}{Q}

V=\dfrac{6.5}{2\times10^{-4}}

V=32500\ volt

Hence, The electric potential difference is 32500 volt.

8 0
3 years ago
While traveling along a highway a driver slows from 24 m/s to 15 m/s in 12 seconds. What is the automobile's acceleration? (Reme
djverab [1.8K]

Considering that while traveling on a road with a<u> final speed of 15 m/s</u>, and an<u> initial speed of 24 m/s</u>, with a given time <u>of 12 seconds.</u>

To calculate the acceleration, we apply the following formula:

α = Vf - Vo/t

We add our data into the formula and solve:

α = 15 m/s - 24 m/s/12 sec

α = -0.75 m/s²

Therefore, the acceleration of the car is -0.75 m/s².

<h2>Skandar</h2>
4 0
2 years ago
If it takes 32,000 joules of heat to warm 750 g of water, what was the temperature change?(the specific heat of water is 4.18 J/
Firdavs [7]

Answer:

10.21°C

Explanation:

From the question,we are given;

  • Quantity of heat = 32,000 Joules
  • Mass of water = 750 g
  • Specific heat capacity of water = 4.18 J/g°C

We are required to calculate the change in temperature;

  • We need to know that quantity of heat is calculated by multiplying mass by specific heat then by change in temperature.
  • That is;

Q = m × c × ΔT

Rearranging the formula;

ΔT = (Q ÷ (m × c))

     = 32,000 J ÷ (750× 4.18 J/g°C)

     = 10.21°C

Therefore, the change in temperature  is 10.21°C

7 0
3 years ago
A loaded 320 kg toboggan is traveling on smooth horizontal snow at 4.60 m/s when it suddenly comes to a rough region. The region
MariettaO [177]

Answer:

367.04 N

Explanation:

Frictional force = mass of the toboggan×deceleration caused by the rough region

Fr = m×ar....................... Equation 1

Where Fr = Average frictional force, m = mass of loaded toboggan, ar = deceleration cause by the rough region.

We can calculate for ar using the formula below

v² = u²+2ars................... Equation 2

make ar the subject of the equation

ar = (v²-u²)/2s.................. Equation 3

Where v = final velocity of the toboggan, u = initial velocity of the toboggan, s = distance or length of the rough region

Given: v = 1.2 m/s, u = 4.6 m/s, s = 8.6 m

Substitute into equation 3

ar = (1.2²-4.6²)/(2×8.6)

ar = (1.44-21.16)/17.2

ar = -19.72/17.2

ar = -1.147 m/s²

Also given: m = 320 kg

Substitute into equation 1

Fr = 320(-1.147)

Fr = -367.04 N

Note: The negative sign tells that the frictional force opposes the motion of the toboggan

6 0
3 years ago
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