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olga2289 [7]
2 years ago
11

Calculate the velocity of a 1650kg satellite that is in a circular orbit of 4.2 x 10^6m above the surface of a planet which has

a radius 3.95 x 10^5 m and the period of the orbit is 2.0 hours.
Physics
1 answer:
Anastasy [175]2 years ago
6 0
-- We're going to be talking about the satellite's speed. 
"Velocity" would include its direction at any instant, and
in a circular orbit, that's constantly changing.

-- The mass of the satellite makes no difference.

Since the planet's radius is  3.95 x 10⁵m  and the satellite is
orbiting  4.2 x 10⁶m  above the surface, the radius of the
orbital path itself is

                               (3.95 x 10⁵m) + (4.2 x 10⁶m)

                     =        (3.95 x 10⁵m) + (42 x 10⁵m)

                     =           45.95 x 10⁵ m

The circumference of the orbit is  (2 π R) =  91.9 π x 10⁵ m.

The bird completes a revolution every 2.0 hours,
so its speed in orbit is

                                     (91.9 π x 10⁵ m) / 2 hr

                        =        45.95 π x 10⁵  m/hr  x  (1 hr / 3,600 sec)

                        =           0.04 x 10⁵      m/sec

                        =              4 x 10³      m/sec  

                                     (4 kilometers per second)
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Explanation:

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adell [148]

Answer:

q = 2.65 10⁻⁶ C

Explanation:

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In this case they indicate that the load is of equal magnitude

       q₁ = q₂ = q

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we calculate

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A ray of red light in air is incident at an angle of 30. on a
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Answer:

20 degrees.

Explanation:

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So, to find θ2, the refracted angle:

sinθ1•1.00029 = sinθ2•1.464

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To the nearest degree,

θ2 = 20 degrees.

8 0
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