Let x = the angle of elevation for shooting the arrow.
Assume
g = 9.8 m/s²
No wind resistance
The vertical launch velocity is 25.1 sin(x) m/s
The horizontal velocity is 25.1 cos(x) m/s
The time of flight is
24/[25.1 cos(x)] s = 0.9562 sec(x) s
Therefore
0.5*[0.9562 sec(x)]*(9.8) = 25.1 sin(x)
4.6854 = 25.1* sin(x)cos(x)
sin(2x) = 0.3733
2x = sin⁻¹ 0.3733 = 21.92 deg
x = 10.96 deg
Answer: 11 degrees (nearest integer)
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Complete Question
The complete question is shown on the first uploaded image
Answer:
The uncertainty in inverse frequency is ![\Delta [\frac{1}{w} ]= \frac{3}{2000} \ s](https://tex.z-dn.net/?f=%5CDelta%20%20%5B%5Cfrac%7B1%7D%7Bw%7D%20%5D%3D%20%20%5Cfrac%7B3%7D%7B2000%7D%20%5C%20s)
Explanation:
From the question we are told that
The value of the proportionality constant is 
The strength of the magnetic field is 
The change in this strength of magnetic field is
The magnetic field is given as

Where
is frequency
The uncertainty or error of the field is given as
![\Delta B = \frac{k }{[\frac{1}{w}^]^2 } \Delta [\frac{1}{w} ]](https://tex.z-dn.net/?f=%5CDelta%20%20B%20%20%3D%20%20%5Cfrac%7Bk%20%7D%7B%5B%5Cfrac%7B1%7D%7Bw%7D%5E%5D%5E2%20%7D%20%20%5CDelta%20%5B%5Cfrac%7B1%7D%7Bw%7D%20%5D)
The uncertainty in inverse frequency is given as
![\Delta [\frac{1}{w} ] = \frac{\Delta B}{k [\frac{1}{w^2} ]}](https://tex.z-dn.net/?f=%5CDelta%20%20%5B%5Cfrac%7B1%7D%7Bw%7D%20%5D%20%20%3D%20%5Cfrac%7B%5CDelta%20B%7D%7Bk%20%5B%5Cfrac%7B1%7D%7Bw%5E2%7D%20%5D%7D)
![\Delta [\frac{1}{w} ]= \frac{\Delta B}{k (B)^2 }](https://tex.z-dn.net/?f=%5CDelta%20%20%5B%5Cfrac%7B1%7D%7Bw%7D%20%5D%3D%20%20%5Cfrac%7B%5CDelta%20B%7D%7Bk%20%28B%29%5E2%20%7D)
substituting values
![\Delta [\frac{1}{w} ]= \frac{3}{5 (20)^2 }](https://tex.z-dn.net/?f=%5CDelta%20%20%5B%5Cfrac%7B1%7D%7Bw%7D%20%5D%3D%20%20%5Cfrac%7B3%7D%7B5%20%2820%29%5E2%20%7D)
![\Delta [\frac{1}{w} ]= \frac{3}{2000} \ s](https://tex.z-dn.net/?f=%5CDelta%20%20%5B%5Cfrac%7B1%7D%7Bw%7D%20%5D%3D%20%20%5Cfrac%7B3%7D%7B2000%7D%20%5C%20s)
Answer:
Explanation:
V = J/C
V = 20/1
= 20 v
Option A is the correct answer