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svlad2 [7]
3 years ago
12

What is the average speed of a kangaroo that hops 60 m in 5 s ?

Physics
2 answers:
jok3333 [9.3K]3 years ago
6 0
The formula for average speed is
v_{avg}= \frac{total distance}{total time}
So we can just substitute our data.
v_{avg}= \frac{60}{5}=12 \frac{m}{s} - its the result
ololo11 [35]3 years ago
6 0

<u></u>
12 m/s that's really easy man, just divide 60 by 5.


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An applicable analogy for part of this activity: The most direct route between San Diego, California, and Caribou, Maine, is abo
PtichkaEL [24]

Answer:

Total time spend = 48.18 hours (Approx)

Explanation:

Given:

Total distance = 5,300 km

Average speed = 110 km / h

Find:

Total time spend

Computation:

Time = Distance / speed

Total time spend = Total distance / Average speed

Total time spend = 5,300 / 110

Total time spend = 48.18 hours (Approx)

3 0
3 years ago
A glass rod rubbed with a tissue paper would strip away electrons from the atoms in glass rod. This would acquire positive charg
Gemiola [76]

Answer:

when this charged glass rod is brought towards the metal ball it will acquire a charge opposite to that of charge body brought close to it without touching it but it will acquire the same charge if the charged object touches it

7 0
3 years ago
Imagine a raindrop starting from rest in a cloud 2 km in the air. If it fell with no air friction at all, it would accelerate to
LenKa [72]

Answer:

2) 433 mph

Explanation:

The final velocity of the raindrop as it reaches the ground can be found by using the equation for a uniformly accelerated motion:

v^2 = u^2 + 2ad

where

v is the final velocity

u = 0 is the initial velocity (the raindrop starts from rest)

a = g = 9.8 m/s^2 is the acceleration due to gravity

d = 2 km = 2000 m is the distance covered

Solving for v,

v=\sqrt{u^2 +2gd}=\sqrt{0^2+2(9.8 m/s^2)(2000)}=198 m/s

And keeping in mind that

1 mile = 1609 metres

1 hour = 3600 s

The speed converted into miles per hour is

v=198 \frac{m}{s}\cdot \frac{3600 s/h}{1609 m/mi}=433 mph

5 0
3 years ago
A 20 kg box on a horizontal frictionless surface is moving to the right at a speed of 4.0 m/s. The box hits and remains attached
yanalaym [24]

Answer:

Work done by the spring is negative

Explanation:

We can answer this question by thinking what is the force acting on the box.

In fact, the force acting on the box is the restoring force of the spring, which is given by Hooke's Law:

F=-kx

where

k is the spring constant

x is the displacement of the box with respect to the equilibrium position of the spring

The negative sign in the equation indicates that the direction of the force is always opposite to the direction of the displacement: so, whether the spring is compressed or stretched, the force applied by the spring on the box is towards the equilibrium position.

The work done by the restoring force is also given by

W=Fx cos \theta

where

F is the restoring force

x is the displacement

\theta is the angle between the direction of the force and the displacement

Here we know that the force is always opposite to the displacement, so

\theta=180^{\circ} \rightarrow cos \theta =-1

Which means that the work done by the spring is always negative, since the direction of the restoring force is always opposite to the direction of motion.

7 0
3 years ago
A step-up transformer has a primary coil with 100 loops and a secondary coil with 1,500 loops. If the primary coil is supplied w
djyliett [7]

(a) The voltage that is produced in the secondary circuit is 1,800 V.

(b) The current that flows in the secondary circuit is 1 A.

<h3>Voltage in the secondary coil</h3>

Np/Ns = Vp/Vs

where;

  • Np is number of turns in primary coil
  • Ns is number of turns in secondary coil
  • Vp is voltage in primary coil
  • Vs is voltage in secondary coil

100/1500 = 120/Vs

Vs = (120 x 1500)/100

Vs = 1,800 V

<h3>Current in the secondary coil</h3>

Is/Ip = Vp/Vs

where;

  • Is is secondary current
  • Ip is primary current

Is = (IpVp)/Vs

Is = (15 x 120)/1800

Is = 1 A

Thus, the voltage that is produced in the secondary circuit is 1,800 V.

Learn more about voltage here: brainly.com/question/14883923

#SPJ1

8 0
2 years ago
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