When we have PH = 9.75
So we can get POH = 14 - 9.75 = 4.25
and when POH = - ㏒[OH-]
by substitution:
4.25 = -㏒[OH-]
∴[OH] = 5.6x10^-5
from this reaction equation:
BOH ↔ B+ + OH-
∴[OH-] = [B+]= 5.6x10^-5 M
and Equ [BOH] = 0.5 m - X
= 0.5 - (5.6x10^-5)
= 0.4999
∴ Kb = [OH-][B+]/[BOH]
= (5.6x10^-5)^2 / 0.4999
= 6.27x10^-9
Boyle’s Boyle’s law I believe is correct answer
Your answer is D. 8.5 x 10^12. Reason is because if you use a calculator (ex. TI-84 Plus C Silver Edition Calculator), it will say 8.5E12, which is represented 8.5 x 10^12.
Hope this helped!
Nate
Following are the advantages of corrosion: A layer of protection: A layer of oxide is formed in surface corrosion, which protects the inner metal from corrosion. Sacrificial anodes such as zinc is used as a preventive measure to stop corrosion of other metals.