Question

A container holds 0.490 m3 of oxygen at an absolute pressure of 5.00 atm. A valve is opened, allowing the gas to drive a piston, increasing the volume of the gas until the pressure drops to 1.20 atm. If the temperature remains constant, what new volume (in m3) does the gas occupy? HINT m3

Answer 1

Answer: The new volume will be $2.04m^3$

Explanation:

To calculate the new volume, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.

The equation given by this law is:

$P_1V_1=P_2V_2$            (at constant temperature)

where,

$P_1\text{ and }V_1$ are initial pressure and volume.

$P_2\text{ and }V_2$ are final pressure and volume.

We are given:

$P_1=5.00atm\\V_1=0.490m^3\\P_2=1.20atm\\V_2=?m^3$

Putting values in above equation, we get:

$5atm\times 0.490m^3=1.20\times V_2\\\\V_2=2.04m^3$

Hence, the new volume will be $2.04m^3$