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Oduvanchick [21]
4 years ago
13

Helium has two valence electrons, and these electrons sre located in the 1s subshell. Without using the periodic table, in which

group and period is helium located?
A .Group 8A, Period 1

B. Group 6A, Period 3

C. Group 3A, Period 3

D. Group 3B, Period 6
Chemistry
2 answers:
gayaneshka [121]4 years ago
8 0

Answer: Option (A) is the correct answer.

Explanation:

Atomic number of helium is 2 and its electronic configuration is 1s^{2}. As here n = 1 this means that helium element belongs to period 1.

Since, helium atom has completely filled s-shell this means that it is unreactive in nature as it neither needs to lose or gain an electron in order to attain stability.

And, all the unreactive elements in the periodic table belongs to group 8A. That is why, helium also belongs to group 8A and period 1.

Thus, we can conclude that helium is located in Group 8A, Period 1 .

solong [7]4 years ago
3 0

The answer iiiis... A: Group 8A, Period 1


<h3>Here's why:</h3>

The way I found this doesn't have much thought or explanation--I just remember that helium and hydrogen are in period 1. The only answer choice with "period 1" is A.

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5 0
3 years ago
PLEASE HELP! Class is almost ending, I don't want to repeat.
nikklg [1K]
ANSWERS:

1. 2KClO_{3} ⇒ 2KCl + 3O_{2}

2. H_{2}  C_{2} O_{4}  + 2NaOH ⇒ Na_{2}  C_{2} O_{4}  + 2 H_{2} O

3. 2 C_{10}  H_{22} +  31O_{2} ⇒ 20C O_{2} + 22 H_{2} O

4. 4 H_{2} + Fe_{3} O_{4} ⇒ 3Fe +4 H_{2} O

5. 4P + 5 O_{2} ⇒ 2 P_{2}  O_{5}


I have attached my work for 1-3. I would like to see if you can get 4 and 5 on your own. but, if you are struggling/copnfused please let me know in the comments! :)

6 0
4 years ago
I know how to solve it with D=M/V and M1V1 however the answer isn’t correct. Help me please
lara31 [8.8K]

Answer:

23.28 g of O2.

Explanation:

We'll begin by calculating the mass of hexane. This can obtain as follow:

Volume of hexane = 10 mL

Density of hexane = 0.66 g/mL

Mass of hexane =?

Density = mass /volume

0.66 = mass of hexane /10

Cross multiply

Mass of hexane = 0.66 x 10

Mass of hexane = 6.6 g

Next, we shall write the balanced equation for the reaction. This is given below:

2C6H14 + 19O2 —> 12CO2 + 14H2O

Next, we shall determine the masses of C6H14 and O2 that reacted from the balanced equation. This can be obtained as follow:

Molar mass of C6H14 = (12.01x6) + (1.008 x 14)

= 72.06 + 14.112

= 86.172 g/mol

Mass of C6H14 from the balanced equation = 2 x 86.172 = 172.344 g

Molar mass of O2 = 16x2 = 32 g/mol

Mass of O2 from the balanced equation = 19 x 32 = 608 g

From the balanced equation above,

172.344 g of C6H14 reacted with 608 g of O2.

Finally, we shall determine the mass of O2 needed to react with 10 mL (i.e 6.6 g) of hexane, C6H14. This can be obtained as follow:

From the balanced equation above,

172.344 g of C6H14 reacted with 608 g of O2.

Therefore, 6.6 g of C6H14 will react with = (6.6 x 608)/172.344 = 23.28 g of O2.

Therefore, 23.28 g of O2 is needed for the reaction.

8 0
3 years ago
At the left.
blondinia [14]

Answer:

i know right answer

Explanation:

let me explain

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