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Anna [14]
4 years ago
10

Suppose the activity of a sample of radioactive material was 100Bq at the start. What would you divide 100Bq by to obtain the ac

tivity at n half-lives after the start?
Physics
1 answer:
myrzilka [38]4 years ago
4 0
If n=1 you divide by 2
If n=2 you divide by 4
If n=3 you divide by 8
so any n you divide by 2 to the power n
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Two blocks with masses m1=0.25kg and m2=1.4kg approach each other along a horizontal, frictionless track. The initial velocities
Alina [70]

Answer:

The energy would remain equal to that of the initial kinetic energy since it is a frictionless surface. However if it is an inelastic collision then energy would be lost due to sound and heat.

Explanation:

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The term time dilation refers to which effect?
RoseWind [281]
Is the apparent loss of time of a moving clock as observed by a stationary observer. Thats what i think.
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Read 2 more answers
Determine the launch speed of a horizontally launched cannonball that lands 26.3
nlexa [21]

Answer:

The cannon has an initial speed of 13.25 m/s.

Explanation:

The launched cannonball is an example of a projectile. Thus, its launch speed can be determined by the application of the formula;

R = u\sqrt{\frac{2H}{g} }

Where: R is the range of the projectile, u is its initial speed, H is the height of the cliff and g is the gravitaty.

R = 26.3 m, H = 19.3 m, g = 9.8 m/s^{2}.

So that:

26.3 = u\sqrt{\frac{2*19.3}{9.8} }

(26.3)^{2} = u^{2} x \frac{38.6}{9.8}

691.69 =  u^{2} x \frac{38.6}{9.8}

u^{2} = \frac{691.69*9.8}{38.6}

   = \frac{6778.562}{38.6}

u^{2} = 175.6104

⇒ u = \sqrt{175.6104}

  = 13.2518

u = 13.25 m/s

The initial speed of the cannon is 13.25 m/s.

4 0
3 years ago
High energy waves have short wave lengths, true or false?
Anna71 [15]
True, the wavelength dies down due to high frequency and low amptitude. 
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The range of temperatures on earth is much less than the range in temperatures on mercury, in part due to the presence of oceans
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