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SashulF [63]
1 year ago
6

A sample of ammonia has a mass of 45.5g. how many molecules are in this sample​

Chemistry
1 answer:
BabaBlast [244]1 year ago
8 0

Answer:

1.61 x 1024 molecules

Explanation:

See image below for step-by-step explanation

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List 3 categories of properties used to classify solids.
NNADVOKAT [17]

Answer : Broadly solids are divided into three categories;

i) Crystalline solids have a regular definite structure, in which the particles pack in a repeating pattern from one edge of the solid to the other.

ii) Amorphous solids have a random structure, with little unorganized pattern long-range order.

iii) Polycrystalline solids are those where an aggregate which consists of a large number of small crystals or grains in which the structure is regular, but the crystals or grains are found to be arranged in a random fashion.

Also solids can be divided into 3 more categories according to their bonds;

i) Covalent solids, like diamond, which forms crystals that can be viewed as a single giant molecule made up of an almost endless number of covalent bonds.

ii) Ionic solids are basically salts, such as NaCl, in which the molecules are held together by the strong force of attraction between ions of opposite charge.

iii) Metallic solids are found in metals which have the force of attraction between atoms of metals, such as copper and aluminum, or alloys, such as brass and bronze, are metallic bonds.


8 0
3 years ago
Read 2 more answers
What is the molarity of a NaCl stock used to make 750 ml of a dilute 10 mM solution if 5 ml of the concentrated solution was use
ch4aika [34]

Explanation:

The given data is as follows.

          M_{1} = 10 mM = 10 \times 10^{-3} M

          V_{1} = 750 ml,           V_{2} = 5 ml

          M_{2} = ?

Therefore, calculate the molarity of given NaCl stock as follows.

                  M_{1} \times V_{1} = M_{2} \times V_{2}

                  10 \times 10^{-3} \times 750 ml = M_{2} \times 5 ml

                   M_{2} = 1.5 M

Thus, we can conclude that molarity of given NaCl stock is 1.5 M.        

7 0
2 years ago
A chemist fills a reaction vessel with mercurous chloride solid, mercury (I) aqueous solution, and chloride aqueous solution at
makvit [3.9K]

Answer:

ΔG° = -533.64 kJ

Explanation:

Let's consider the following reaction.

Hg₂Cl₂(s) ⇄ Hg₂²⁺(aq) + 2 Cl⁻(aq)

The standard Gibbs free energy (ΔG°) can be calculated using the following expression:

ΔG° = ∑np × ΔG°f(products) - ∑nr × ΔG°f(reactants)

where,

ni are the moles of reactants and products

ΔG°f(i) are the standard Gibbs free energies of formation of reactants and products

ΔG° = 1 mol × ΔG°f(Hg₂²⁺) + 2 mol × ΔG°f(Cl⁻) - 1 mol × ΔG°f(Hg₂Cl₂)

ΔG° = 1 mol × 148.85 kJ/mol + 2 mol × (-182.43 kJ/mol) - 1 mol × (-317.63 kJ/mol)

ΔG° = -533.64 kJ

3 0
3 years ago
Reaction of (r)-2-chloro-4-methylhexane with excess nai in acetone gives racemic 2-iodo-4-methylhexane. what is the explanation
saveliy_v [14]

I believe this question has the following five choices to choose from:

 

>an SN2 reaction has occurred with inversion of configuration

>racemization followed by an S N 2 attack

>an SN1 reaction has taken over resulting in inversion of configuration

>an SN1 reaction has occurred due to carbocation formation

>an SN1 reaction followed by an S N 2 “backside” attack

 

 

The correct answer is:

an SN1 reaction has occurred due to carbocation formation 

4 0
3 years ago
A solid with a density of 3.57g/mL and mass of 19.5g is added to a graduated cylinder that contain 23.2mL of water. What is the
NNADVOKAT [17]

Answer:

Volume of liquid = 28.7 mL

Explanation:

Given data;

Density of solid = 3.57 g/ml

Mass of solid = 19.5 g

Volume of water = 23.2 mL

Total volume when solid is dropped into graduated cylinder= ?

Solution:

Density = mass/ volume

v = m/d

v = 19.5 g/ 3.57 g/ml

v = 5.5 mL

Volume of liquid = volume of water + volume of solid

Volume of liquid = 23.2 mL + 5.5 mL

Volume of liquid = 28.7 mL

3 0
2 years ago
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