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3 years ago

Prevailing winds peru

1 answer:

3 0

In the afternoons the prevailing direction is South-East with recurrent low wind and calm that averages 30%. Overcast (cloudy): Lima has a lot of months under ...

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Do the following calculation and express the answer using correct scientific notation. (6.00x10^23)y(3.00)/284)

Naily [24]

I know its not the answer but i had to put something bc im jus setting this up im rlly sorry for the inconvenience but i looked it up n got a quizlet n the answer on there was 1.81x10^-4 if it helps

5 0

3 years ago

¿la densidad de una solución es mayor o menor al agregar agua?

andreev551 [17]

Answer:

La densidad experimenta una disminución

Explanation:

Hola!

En este caso, debemos recordar que la adición de agua incrementa el volumen donde se encuentra un soluto disuelto, el cual posee una cantidad de materia constante. De este modo, sabiendo que la densidad es:

$\rho =\frac{m}{V}$

Al incrementar el denominador (volumen), la densidad experimenta una disminución, al estar en relación inversamente proporcional.

Muchos saludos!

5 0

3 years ago

How do you express 0.00026 in scientific notation

Rus_ich [418]

2.6x10negative4power 2.6x10^-4

6 0

4 years ago

Read 2 more answers

How many mL of 0.506 M HClare needed to dissolve 9.85 g of BaCO3?

Blababa [14]

Answer:

197mL of 0,506M HCl

Explanation:

The reaction of HCl + BaCO₃ is:

BaCO₃(s) + 2HCl → BaCl₂(aq) + CO₂ + H₂O.

The moles of BaCO₃ in 9,85 g are:

9,85 g of BaCO₃ × $\frac{1mol}{197,34 g}$ = 0,0499 moles of BaCO₃

As 1 mol of BaCO₃ reacts with two moles of HCl, for a complete reaction of BaCO₃ to dissolve this compound in water you need:

0,0499 moles of BaCO₃ × $\frac{2molHCl}{1molBaCO_{3}}$ = 0,0998 moles of HCl

If you have a 0,506M HCl, you need to add:

0,0998 moles of HCl× $\frac{1L}{0,506moles}$ = 0,197 L ≡ 197mL

I hope it helps!

8 0

3 years ago

An unidentified compound contains only phosphorous and fluorine, meaning we could write its formula as PxFy. Heating 0.2324 g of

cricket20 [7]

Answer:

The molecular formula of the compound is P2F4

Explanation:

Step 1: Data given

Mass of the compound = 0.2324 grams

Volume of container = 378 mL

Pressure at 77 °C = 97.3 torr

The gaseous PxFy was then reacted with an aqueous solution of calcium chloride, and all of the fluorine was converted to 0.2631 g of CaF2.

Molar mass CaF2 = 78.07 g/mol

Step 2: Calculate moles CaF2

Moles CaF2 = 0.2631 g/ 78.07 g/mol=0.003370

Step 3: Calculate moles F

For every 1 mol CaF2 we have 1 mol Ca2+ and 2 moles F-

moles F- = 2 * 0.003370=0.006740

Step 4: Calculate mass of F

mass F = 0.006740 mol * 19.00 g/mol=0.1281 g

Step 5: Calculate mass of P

mass P = mass of compound - mass of F = 0.2324 - 0.1281 =0.1043 g

Step 6: Calculate moles P

moles P = 0.1043 g/ 30.97 g/mol=0.003368 moles

Step 7: Calculate mol ratio

We divide by the smallest amount of moles

P: 0.003368/0.003368 =1

F: 0.006740/ 0.003368 =2

The empirical formula is PF2

The empirical formula has a molar mass of 68.97 g/mol

Step 8: Calculate moles of compound

p*V = n*R*T

n = (p*V)/(R*T)

⇒ with p = the pressure of the gas = 97.3 torr = 97.3/760 = 0.128 atm

⇒ with V = the volume of the gas = 0.378 L

⇒ with R = the gas constant = 0.08206 L*atm/K*mol

⇒ with T = the temperature = 77.0 °C = 350 Kelvin

Number of moles =(0.128 *0.378)/(0.08206*350)

Number of moles =

moles gas = pV/RT = 0.128 atm x 0.378 dm^3/ 0.08206x350 K=0.00168

Step 9: Calculate molar mass

Molar mass = mass / moles

Molar mass = 0.2324 grams / 0.00168 moles

Molar mass = 138 g/mol

Step 10: Calculate the molecular formula

138.0 / 68.97 = 2

2*(PF2) = P2F4

The molecular formula of the compound is P2F4

4 0

3 years ago