Prevailing winds peru

Round to 4 significant figures. 35.5450

IrinaVladis [17]

Answer:

no sé m i e r d a ..............

Explanation:

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8 0

3 years ago

Read 2 more answers

What is the mass of 6.2 mil of K2CO3

Oksi-84 [34.3K]

Answer:

6.2 moles of K2CO3 can be converted to 856.8741 grams.

6 0

3 years ago

The image shows sedimentary rock layers with index

vichka [17]

Layer 2 and layer 9 are the same relative age.

Explanation:

The statement that best describes the rock layers is that Layer 2 and layer 9 are the same relative age..

The relative age is used in placing sedimentary rocks in order of their occurrence.

To do this, we apply the sedimentary laws.

The ones applicable here are:

Principle of superposition states that in an undisturbed sequence, the oldest layer is at the base and youngest on top.
Principle of cross cutting states that a fault and intrusion are younger than the rocks they cut through.
Principle of fossil and fauna succession states that fossils and fauna succeed on another in a determinable form.

We see that layers 2 and 9 have the same fossil and are the same lithological units.

learn more:

Sedimentary rocks brainly.com/question/2740663

#learnwithBrainly

5 0

3 years ago

Explain the law of conservation of energy.

Ulleksa [173]

<h2>Energy is conserved. It never appears or disappears. It just changes from one kind of type to another. The Universe contains the same amount of energy it started with. This amount can never change.</h2><h2></h2>

6 0

3 years ago

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A 50 L cylinder is filled with argon gas to a pressure of 10130.0 kPa at 300°C. How many moles of argon gas does the cylinder co

KengaRu [80]

In this problem, we need to use the ideal gas law. The following is the formula used in ideal gas law: PV = nRT, where n refers to the moles and R is the gas constant.

Given
P = 10130.0 kPa
V = 50 L
T = 300 degree celcius + 273.15 = 573.15 K
R = 8.314 L. kPa/K.mol

Solution
To get the moles which represent the "n" in the formula, we need to rearrange the equation.

PV = nRT PV
---- ------ ---> n = --------
RT RT RT

10130.0 kPa x 50 L
n= ---------------------------------------------
8.314 L. kPa/K.mol x 573.15 K
506,500
= ----------------------------
4,765.17 mol K

=106.29 mol Ar

So the moles of argon gas is 106.29 moles

8 0

3 years ago

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