The total energy released per gram of methane burnt is 119,941.3 J/g.
<h3>Energy absorbed by water</h3>
Q = mcΔθ
where;
- m is mass of water
- c is specific heat of water
- Δθ is change in temperature
Q = (500)(4.184)(68 - 25)
Q = 89,956 J
<h3>Total energy released per gram of methane burnt</h3>
0.3T = 89,956 J
T = 89,956 J/0.3
T = 299,853.3 J
Total energy per gram of methane, E = T.E/m
E = (299,853.3 J) / (2.5 g)
E = 119,941.3 J/g
Thus, the total energy released per gram of methane burnt is 119,941.3 J/g.
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48.78%
Percentage of MgSO4 = mass of MgSO4/ mass of sample (MgSO4. 7H20) and multiply it by 100.
Answer: Δn for the following equation in relating Kc to Kp is 2.
Explanation:
The balanced chemical equation is:

Relation of
with
is given by the formula:
Where,
= equilibrium constant in terms of partial pressure
= equilibrium constant in terms of concentration
R = Gas constant
T = temperature
= change in number of moles of gas particles =
Putting values in above equation, we get:
Thus the value of Δn for the following equation in relating Kc to Kp is 2.
All vascular plants have vascular tissue which allows the transport of water, nutrients and food between the ground and the body of the plant. So your answer would be that the internal structures of vascular plants transport food and water through their vascular tissue. Hope this helps!<span />
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