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lions [1.4K]
3 years ago
6

In Parts I and II of the lab, what happened to the electrons of each element to produce the different colors of light? Explain y

our answers using important terms from the lesson and information provided in the laboratory.
Chemistry
1 answer:
RoseWind [281]3 years ago
4 0

Answer: Electrons must be heated to emitted light. When heat was added to the elements,the electrons absorbs the energy and moves to its excited state. Once the electronstarts to fall back to a lower orbit, it emits energy in the form of light. Thedifferent lights being emitted, depends on their wavelength

Explanation: I did the Quantization of Energy Lab

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Need help setting the problem up
Sveta_85 [38]

Answer:

4.0 moles

Explanation:

The following data were obtained from the question:

Volume (V) = 12L

Pressure = 5.6 atm

Temperature (T) = 205K

Gas constant (R) = 0.08206 atm.L/Kmol

Number of mole (n) =?

Using the ideal gas equation: PV = nRT, the number of mole of the gas can be obtained as follow

PV = nRT

5.6 x 12 = n x 0.08206 x 205

Divide both side by 0.08206 x 205

n = (5.6 x 12)/(0.08206 x 205)

n = 4.0 moles

Therefore, the number of mole of the gas is 4.0 moles

5 0
3 years ago
A sample was then prepared containing 14.00 mL of coffee and 8.00 mL of 4.80 ppm Li , and diluted to a 50.00 mL total volume. Th
mafiozo [28]

Answer:

The right answer is "[Na^+]=5.57 \ ppm".

Explanation:

The given values are:

\frac{A_s}{A_{coffee}} =\frac{0.840}{1.000}

According to the question,

The concentration of standard will be:

=  \frac{7.80}{50.00}\times 4.80

=  0.156\times 4.80

=  0.748 \ ppm

Coffee after dilution,

⇒  \frac{A_{coffee}}{C_{coffee}} =F\times \frac{A_s}{C_s}

or,

⇒  C_{coffee}=\frac{A_{coffee}}{A_s}\times \frac{C_s}{F}

On substituting the values, we get

⇒               =\frac{1.000}{0.840}\times \frac{0.748}{1.68}

⇒               =1.191\times 1.3104

⇒               =1.561 \ ppm

hence,

In unknown sample, the concentration of coffee will be:

=  1.561\times \frac{50}{14}

=  \frac{78.05}{14}

=  5.57 \ ppm

7 0
3 years ago
I need helpp please last day i can take this
Nuetrik [128]
A is your answer  Have a wonderful day 
7 0
3 years ago
Read 2 more answers
All alkali earth metals have the same reactivity with water. True or False
zheka24 [161]
True.  Water is a neutral substance so nothing should react to it, this makes it so that no matter how basic a metal is, it reacts the same to water.
4 0
3 years ago
Mole ratio practice worksheet part 1
Arlecino [84]
2. 0.05733 mol CuCl2 (1 mol Cu(OH)2 / 1 mol CuCl2) = 0.05733 mol Cu(OH)2 <-- It's the same because there's a 1:1 ratio between the reactant and the product.
7 0
2 years ago
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