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Varvara68 [4.7K]
3 years ago
8

Fill in the left side of this equilibrium constant equation for the reaction of nitrous acid (HNO_2) with water.

Chemistry
2 answers:
koban [17]3 years ago
6 0

Answer:

1. The equilibrium equation for the reaction between nitrous acid (HNO2) and water (H2O) is given below:

HNO2(aq) + H2O(l) <=> H3O+(aq) + NO2- (aq)

2. Ka = [H3O+] [NO2-] / [HNO2]

Explanation:

1. Step 1:

The reaction of nitrous acid HNO2 acid with water.

When nitrous acid react with water, it will produce hydronium ion (H3O+) and the corresponding nitrite ion (NO2-). This is so because an acid will dissolves in water to produce hydronium ion as the only positive ion. The equation is illustrated below:

HNO2(aq) + H2O(l) <=> H3O+(aq) + NO2- (aq)

2. Step 2:

Writing the Ka for the above equation. This is illustrated below:

The Ka is given by:

Ka = [H3O+] [NO2-] / [HNO2]

mafiozo [28]3 years ago
5 0

Answer:

Ka=\frac{[H^+][NO_2^-]}{[HNO_2]}

Explanation:

The reaction

The reaction of nitrous acid with water is a dissociation reaction of an acid:

HNO_2(aq) + H_2O(l) \longrightarrow H^+(aq) + NO_2^-(aq) + H_2O(l)

HNO_2(aq) \longrightarrow H^+(aq) + NO_2^-(aq)

The Ka equation

Ka=\frac{[H^+][NO_2^-]}{[HNO_2]}

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