Given :
Some compounds :
.
To Find :
Which of the following compounds has the most deshielded protons .
Solution :
Deshielded means nucleus whose chemical shift has been increased due to removal of electron density, magnetic induction, or other effects .
In simple words deshielding means the ability to shift protons .
Now , among Cl , I , Br and H . Cl is the most electron negative .
Therefore , deshielding will be more in
.
Hence , this is the required solution .
Yo sup??
Let the percentage of K-39 be x
then the percentage of K-40 is 100-(x+0.01)
We know that the net weight should be 39.5. Therefore we can say
(39*x+40*(100-(x+0.01))+38*0.01)/100=39.5
(since we are taking it in percent)
39*x+40*(100-(x+0.01))+38*0.01=3950
39x+4000-40x-0.4+0.38=3950
2x=49.98
x=24.99
=25 (approx)
Therefore K-39 is 25% in nature and K-40 is 75% in nature.
Hope this helps.
We know that density = mass /volume
so
mass=volume*density
volume=mass/density
so c is wrong
It’s Benzene, I do believe :) hope this helped, good luck!
Answer:
1 A
3 main types of bond are
Ionic bond ( formed due to complete transfer of electron between atoms(
Covalent bond ( formed by mutual sharing of electron)
Metalic bond ( present in the metals due to mobile electrons)
1 B bond in CaO is ionic bond formation in attached image
1 C hydrogen bond with nitrogen is covelent NH3 ammonia is formed because a bond between two non metals is expected to be covalent
More their electronegativity difference between hydrogen and nitrogen is less than 1.7 that makes it covalent
Explanation: