1) Chemical equation
<span>2NH4Cl(s)+Ba(OH)2⋅8H2O(s)→2NH3(aq)+BaCl2(aq)+10H2O(l)
2) Stoichiometric ratios
2 mol NH4Cl(s) : 54.8 KJ
3) Convert 24.7 g of NH4Cl into number of moles, using the molar mass
molar mass of NH4Cl = 14 g/mol + 4*1 g/mol + 35.5 g/mol = 53.5 g/mol
number of moles = mass in grams / molar mass
number of moles = 24.7 g / 53.5 g/mol = 0.462 moles
4) Use proportions:
2 moles NH4Cl / 54.8 kJ = 0.462 moles / x
=> x = 0.462 moles * 54.8 kJ / 2 moles = 12.7 kJ
Answer: 12.7 kJ</span>
Answer:
1 dihydrogen reacts with 1 chlorine to form two hydrogen chloride (edit: hydrogen chloride is also referred to as hydrochloric acid)
<span>the table say that at 20 degree celcius 88.0g of NANO3 will remain dissolved in
100 gm of H2O
so at 20 degree celcius 80.0g of H20 will dissolve
(88.0g)x(80g/100g)=70.4g of NANO3
so at 20 degree celcius
86.3g-70.4g= 15.9 gram of NANO3 will come out of solution.</span>
