For this problem, we use Graham's Effusion Law to find out the rate of effusion of chlorine gas. The formula is as follows:
R₁/R₂ = √(M₂/M₁)
Let 1 be N₂ while 2 be Cl₂
255/R₂ = √(28/70.8)
Solving for R₂,
R₂ = 405.5 s
<em>Thus, it would take 405.5 s to effuse chlorine gas.</em>
Answer:
3: Lactone
Explanation:
Lactones are defined as carboxylic esters that contain the structure (−C(=O)−O−) which is essentially showing that an ester has now become part of the chemical structure of the ring.
Thus, looking at the question, it has the structure as defined in Lactones.
Thus, we can say that the compound is a Lactone.
Answer:
I think that the answer is A.
A cleaning solution with an OH⁻ concentration of 2.5 × 10⁻⁴ mol/L, has a pH of 10.4 and is basic (options b and c).
<h3>How can we determine the acidity or basicity of a solution?</h3>
- If pH < 7, the solution is acid.
- If pH = 7, the solution is neutral.
- If pH > 7, the solution is basic.
- Step 1. Calculate the pOH of the solution.
The hydroxide ion concentration is 2.5 × 10⁻⁴ mol/L.
pOH = -log [OH⁻] = log (2.5 × 10⁻⁴) = 3.6
- Step 2. Calculate the pH of the solution.
We will use the following expression.
pH + pOH = 14
pH = 14 - pOH = 14 - 3.6 = 10.4
Since pH > 7, the solution is basic.
A cleaning solution with an OH⁻ concentration of 2.5 × 10⁻⁴ mol/L, has a pH of 10.4 and is basic (options b and c).
Learn more about pH here: brainly.com/question/172153
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