Heat gained by ice cubes would be equal to the - heat lost by warm water
The moles of ice is: 50.5 g / 18.0 g/mol = 2.81 mol
Heat required to melt all of the ice is equal to: 2.81 mol X 6.02 kJ/mol = 16.9 kJ = 16890 J
Now, know whether the warm water will still be above 0C when it loses this much heat:
-1690 J = 160 g (4.184 J/gC) (Delta T) Delta T = -25C
In order to solve for the final temperature, going back to include warming of the melted ice to a final temperature:
q(ice/water) = - q(warm water)
moles (Delta Hf) + m c (T2-T1) = - m c (T2-T1)
50.5 g / 18.0 g/mol = 2.81 mol
2.81 mol X 6.02 kJ/mol + 50.5g (4.184 J/gC) (T2-0) = -160g (4.184 J/gC) ( T2-80)
16916 + 211.3T2 = -669.4 T2 + 53555
36639 = 880.7 T2
T2 = 41.6 C
The density of the stone is 5 g/cm³.
Mass = 25 g
Volume = 7 mL – 2 mL = 5 mL = 5 cm³
Density = mass/volume = 25 g/5 cm³ = 5 g/cm³
Answer:
Carbon is a highly covalent element due to the presence of four valence electrons in its outermost shell. This helps it bond covalently with other elements in various ways.
Carbon is known to be the backbone for most compounds. The carbon backbone vary in length and in the mode of bonding such as having the ability to from straight, branched, rings, double or triple bond which contibutes to the diversity and complexity of organic molecules.
Answer:
%Cl would be too high if not dried.
Explanation:
Cl (chlorine) is a liquid. During the process of drying AgCl, the chlorine particles evaporate and chlorine is lost.
