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choli [55]
3 years ago
15

When mixed, solutions of silver nitrate, AgNO3, and sodium sulfate, Na2SO4, form a precipitate of silver sulfate, Ag2SO4. The ba

lanced equation is:
Chemistry
1 answer:
Maslowich3 years ago
3 0

Answer:

2 AgNO3 + Na2SO4 → Ag2SO4 + 2 NaNO3

Explanation:

The general schemefor a reaction is given as;

Reactants --> Products

In this question, the reactants are AgNO3 and Na2SO4. The product is Ag2SO4.

The equation is given as;

AgNO3 + Na2SO4 --> Ag2SO4

The other poduct formed in this reaction is NaNO3.

The full reaction is given as;

AgNO3 + Na2SO4 --> Ag2SO4 + NaNO3

The above reaction is not balanced because there are unequal number of atoms of the elements on both sides of the reaction.

The balanced equation is given as;

2 AgNO3 + Na2SO4 → Ag2SO4 + 2 NaNO3

In this equation, there are equal number of moles of the atoms on both sides.

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In what area of the united states do the fewest people live​
fiasKO [112]

Answer:

The most populous state in the United States is California, which has 37,253,956 inhabitants. On the other hand, the least populated state is Wyoming with 493,782 inhabitants.

6 0
3 years ago
Read 2 more answers
What are the substances you start with in a chemical reaction called
Veronika [31]

A chemical reaction is the process in which atoms present in the starting substances rearrange to give new chemical combinations present in the substances formed by the reaction. These starting substances of a chemical reaction are called the reactants, and the new substances that result are called the products.

8 0
3 years ago
Now we need to find the amount of NF3 that can be formed by the complete reactions of each of the reactants. If all of the N2 wa
Alex777 [14]

The question is incomplete, the complete question is:

Nitrogen and fluorine react to form nitrogen fluoride according to the chemical equation:

N_2(g)+3F_2(g)\rightarrow 2NF_3(g)

A sample contains 19.3 g of N_2 is reacted with 19.3 g of F_2. Now we need to find the amount of NF_3 that can be formed by the complete reactions of each of the reactants.

If all of the N_2 was used up in the reaction, how many moles of NF_3 would be produced?

<u>Answer:</u> 1.378 moles of NF_3 are produced in the reaction.

<u>Explanation:</u>

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}       ......(1)

Limiting reagent is defined as the reagent which is completely consumed in the reaction and limits the formation of the product.

Excess reagent is defined as the reagent which is left behind after the completion of the reaction.

In the given chemical reaction, N_2 is considered as a limiting reagent because it limits the formation of the product and it was completely consumed in the reaction.

We are given:

Mass of N_2 = 19.3 g

Molar mass of N_2 = 28.02 g/mol

Putting values in equation 1:

\text{Moles of }N_2=\frac{19.3g}{28.02g/mol}=0.689mol

For the given chemical reaction:

N_2(g)+3F_2(g)\rightarrow 2NF_3(g)

By the stoichiometry of the reaction:

1 mole of N_2 produces 2 moles of NF_3

So, 0.689 moles of N_2 will produce = \frac{2}{1}\times 0.689=1.378mol of NF_3

Hence, 1.378 moles of NF_3 are produced in the reaction.

8 0
3 years ago
If the reaction of 23.3 grams of Cr2O3 produces 5.35 grams<br> of Al2O3, what is the percent yield?
Marat540 [252]

Answer:

34.2%

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

Cr₂O₃ + 2Al —> Al₂O₃ + 2Cr

Next, we shall determine the mass of Cr₂O₃ that reacted and the mass of Al₂O₃ produced from the balanced equation. This can be obtained as follow:

Molar mass of Cr₂O₃ = (52×2) + (3×16)

= 104 + 48

= 152 g/mol

Mass of Cr₂O₃ from the balanced equation = 152 × 1 = 152 g

Molar mass of Al₂O₃ = (27×2) + (16×3)

= 54 + 48

= 102 g/mol

Mass of Al₂O₃ from the balanced equation = 1 × 102 = 102 g

SUMMARY:

From the balanced equation above,

152 g of Cr₂O₃ reacted to produce 102 g of Al₂O₃.

Next, we shall determine the theoretical yield of Al₂O₃. This can be obtained as follow:

From the balanced equation above,

152 g of Cr₂O₃ reacted to produce 102 g of Al₂O₃.

Therefore, 23.3 g of Cr₂O₃ will react to produce = (23.3 × 102)/152 = 15.64 g of Al₂O₃.

Thus, the theoretical yield of Al₂O₃ is 15.64 g.

Finally, we shall determine the percentage yield of Al₂O₃. This can be obtained as follow:

Actual yield of Al₂O₃ = 5.35 g

Theoretical yield of Al₂O₃ = 15.64 g.

Percentage yield of Al₂O₃ =?

Percentage yield = Actual yield /Theoretical yield × 100

Percentage yield = 5.35 / 15.64 × 100

Percentage yield of Al₂O₃ = 34.2%

3 0
3 years ago
What is displacement reaction?​
Sauron [17]

Answer:

it is a chemical reaction in which one element replaces an/other element in a compound. It can be represented generically as: A + B-C → A-C + B This will most often occur if A is more reactive than B, thus giving a more stable product.

4 0
4 years ago
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