Answer:
The procedure with the simple calorimeter to compare the energy released by different fuels is described below in detail.
Explanation:
If the response delivers heat (rxn < 0), then heat is consumed by the calorimeter (calorimeter > 0), and its temperature improves. Conversely, if the response consumes heat (rxn > 0), suddenly heat is carried from the calorimeter to the arrangement (calorimeter < 0), and the temperature of the calorimeter drops.
The valency of Al₂O₃ is 0 because each element in the compound has its outer most shell completely filled so it cannot obtain electrons of donate them since it is in its stable-most form.
Answer:
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120 grams of Carbon-14 decays to 15 grams in 17,190 years.
Answer:
<em>A solution containing 60 grams of nano3 completely dissolved in 50. Grams of water at 50°c is classified as being</em> <u>supersaturaded</u>
Explanation:
This question is about solubility.
Regarding solubility, the solutions may be classified as:
- Unsaturated: the concentration is below the maximum concentration permited at the given temperature.
- Saturated: the concentration is the maximum permitted at the given temperature, under normal conditions.
- Supersaturated: the concentration has overcome the maximum permitted at the given temperature. This is possible only under special conditions and is a very unstable state.
Each substance has its own, unique solubility properties. So, in order to tell the state of the solution you need to compare with either solubility tables, or solubility curves; or run you own experiments.
- In internet you can find the solubility curve of NaNO₃ showing the solubility for a wide range of temperatures.
- In such curve the solubility of NaNO₃ at 50°C is about 115 g of NaNO₃ per 100 g of water.
- Hence, do the proportion to determine the amount of solute that can be dissolved in 50 grams of water at 50°CÑ
115 g NaNO₃ / 100 g H₂O = x / 50 g H₂O ⇒ x = 57.5 g NaNO₃
- <u>Conclusion</u>: 50 grams of water can contain 57.5 g of NaNO₃ dissolved; so, <em>a solution containing 60 g of NaNO₃ completely dissolved in 50 grams of water is supersaturated.</em>
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