seaweed having 50 g salt in 1 L water. The bucket contains 150 g of salt in 2 L of water
amount of water present in bucket is twice to amount of water in weed

At equilibrium, volume of water in weed is x and volume in bucket is y but concentration remain same as follows:

At equilibrium, weed loose z L from 1 L water to bucket containing 2 L as follows:

Thus, Weed will loose 0.25 L of water
Answer : C.
3 meters=3000 millimeters
Answer:
bacause god was like nah we don't play that game around here so he was like ig blue my fav color ;)
Explanation:
Answer:
3.5 mol
Explanation:
Step 1: Given data
Moles of HCl: 7.0 mol
Step 2: Write the balanced equation
Fe(s) + 2 HCl(aq) ⇒ FeCl₂(aq) + H₂(g)
Step 3: Calculate the moles of H₂ gas produced from 7.0 moles of HCl
According to the balanced equation, the molar ratio of HCl to H₂ is 2:1.
7.0 mol HCl × 1 mol H₂/2 mol HCl = 3.5 mol H₂