Answer:
pH = 7.8
Explanation:
The Henderson-Hasselbalch equation may be used to solve the problem:
pH = pKa + log([A⁻] / [HA])
The solution of concentration 0.001 M is a formal concentration, which means that it is the sum of the concentrations of the different forms of the acid. In order to find the concentration of the deprotonated form, the following equation is used:
[HA] + [A⁻] = 0.001 M
[A⁻] = 0.001 M - 0.0002 M = 0.0008 M
The values can then be substituted into the Henderson-Hasselbalch equation:
pH = 7.2 + log(0.0008M/0.0002M) = 7.8
The reaction is
FeO + Fe3O4 + 1/2 O2---> 2Fe2O3
Thus as shown in the balanced equation two moles of Fe2O3 are formed when 0.5 moles of O2 reacted with mixture of FeO and Fe3O4
moles of Fe2O3 = MAss / Molar mass = 4.141 / 159.69 = 0.0259 moles
So moles of O2 needed = 0.5 X 0.0259 = 0.01295
Mass of O2 = moles X molar mass = 0.01295 X 32 = 0.4144 grams
Answer:
Explanation:
2Al(s) + 3 2 O2(g) → Al2O3(s) And given the stoichiometry ...and EXCESS dioxygen gas...we would get 6.25⋅ mol of alumina. the which represents a mass... ...6.25 ⋅ mol ×101.96 ⋅ g ⋅ mol−1 molar mass of alumina ≡ 637.25 ⋅ g.
Explanation:
The species or elements which gain electrons and reduces itself are known as oxidizing agent or oxidant.
Ability of an element to act as an oxidizing agent depends on its electrode potential.
The electrode potential of 
is 0.52 V.
The electrode potential of 
is -0.41 V.
The electrode potential of 
is -2.38 V.
Greater is the value of electrode potential, stronger will be the oxidizing agent.
Therefore, rank of these species by their ability to act as an oxidizing agent are as follows.
> >
Answer:
Stannic fluoride, SnF4
Explanation:
The chemical formula of Barium nitride is Ba(NO3)2.
The chemical formula of Cobaltous chloride is COCl2.
The chemical formula of Sodium Oxide is Na2O.
So the correct one is stannic fluoride, SnF4.
