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3 years ago

When do you use parentheses in writing a chemical formula?

1 answer:

7 0

In general, When writing the chemical formula of a compound that contains a polyatomic ion, in order to indicate more than one polyatomic ion in the formula, putparentheses around the polyatomic ion before writing the subscript.

Hope this helps. :)

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Someone help me please.. I will mark as brainliest I promise...

Kobotan [32]

Answer:

(a) proton

(b) neutron

particles in nucleus are proton and neutron.

atom is electrically neutral because no.of proton= no.of electron=6

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3 years ago

What is the H+ in solution with pH of 10.9

Soloha48 [4]

Answer:

Explanation:

has a pH of 6.6, then what is the H3O+ in solution X? View Answer · What is the pOH of a solution in which (H+)

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3 years ago

When using a dichotomous key to identify organisms what do we look at

Inga [223]

Answer:

a. physical features

Explanation:

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3 years ago

Explain why a climax community is not always a forest.

kaheart [24]

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3 years ago

Find the potentials of the following electrochemical cell:

melomori [17]

Answer: 0.18 V

Explanation:-

$Cd/Cd^{2+}(0.10M)//Ni^{2+}(0.50M)?Ni$

Here Cd undergoes oxidation by loss of electrons, thus act as anode. nickel undergoes reduction by gain of electrons and thus act as cathode.

$E^0_(Cd^{2+}/Cd)$ =-0.40V[/tex]

$E^0_(Ni^{2+}/Ni)$ =-0.24V[/tex]

$Cd+Ni^{2+}\rightarrow Cd^{2+}+Ni$

Here Cd undergoes oxidation by loss of electrons, thus act as anode. nickel undergoes reduction by gain of electrons and thus act as cathode.

$E^0=E^0_{cathode}- E^0_{anode}$

Where both $E^0$ are standard reduction potentials.

$E^0=E^0_{[Ni^{2+}/Ni]}- E^0_{[Cd^{2+}/Cd]}$

$E^0=-0.24-(-0.40)=0.16V$

Using Nernst equation :

$E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Cd^{2+}]}{[Ni^{2+]}$

where,

n = number of electrons in oxidation-reduction reaction = 2

$E^o_{cell}$ = standard electrode potential = 0.16 V

$E_{cell}=0.16-\frac{0.0592}{2}\log \frac{[0.10]}{[0.5]}$

$E_{cell}=0.18V$

Thus the potential of the following electrochemical cell is 0.18 V.

6 0

3 years ago