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RideAnS [48]
3 years ago
13

Muscles use force to move objects. When using a ramp to do work, would your muscles use more force or less force?

Physics
2 answers:
White raven [17]3 years ago
7 0
Less because the ramp is letting off force but i does depend on the way you are going on the ramp

Mademuasel [1]3 years ago
4 0
If it's up then more if it's down then less
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Two stars in a faraway part of the Milky Way are orbiting each other as a binary star system. By
natita [175]

Answer: M_{total}= 1.85

Explanation: Estimate the total mass of a binary system is done by a reformulation of <em>Kepler's Third Law</em>, which states that the square of the period of a planet's orbit is proportional to the cube of its semimajor axis, i.e.:

a^{3}=(M_{1}+M_{2})P^{2}

where

a is semimajor axis in astronomical units (AU);

P is period measured in years;

M_{1}+M_{2} is total mass of the two-stars system;

For the two stars faraway in the Milky Way:

1 year is equivalent of 365 days, so period in years:

P=\frac{594}{365}

P = 1.63 years

Calculating total mass:

a^{3}=(M_{total})P^{2}

M_{total}=\frac{a^{3}}{P^{2}}

M_{total}=\frac{1.7^{3}}{1.63^{2}}

M_{total}= 1.85

<u>The total mass of the two-object system is 1.85 mass units.</u>

3 0
3 years ago
Suppose you have 600.0 grams of room temperature water (20.0 degrees Celsius) in a thermos. You drop 90.0 grams of ice at 0.00 d
IrinaK [193]

Answer:

T_{f} = 7.02 ° C

Explanation:

The liquid water gives heat to melt the ice (Q₁) maintaining the temperature of 0 ° C and then the two waters are equilibrated to a final temperature.

Let's start by calculating the heat needed to melt the ice

Q₁ = m L

Q₁ = 0.090 3.33 10⁵

Q₁ = 2997 10⁴ J

This is the heat needed to melt all the ice

Now let's calculate at what temperature the water reaches when it releases this heat

Q = M c_{e} (T₀ -T_{f})

Q₁ = Q

    T_{f} = T₀ - Q₁ / M c_{e}

T_{f} = 20.0 - 2997 104 / (0.600 4186)

T_{f}= 20.0 - 11.93

T_{f} = 8.07 ° C

This is the temperature of the water when all the ice is melted

Now the two bodies of water exchange heat until they reach an equilibrium temperature

Temperatures are

Water of greater mass     T₀₂ = 8.07ºC

Melted ice                         T₀₁ = 0ºC

M c_{e} (T₀₂ - T_{f}) = m c_{e} (T_{f} - T₀₁)

      M T₀₂ + m T₀₁ = m T_{f}+ M T_{f}

T_{f}= (M T₀₂ + 0) / (m + M)

T_{f} = M / (m + M) T₀₂

let's calculate

T_{f} = 0.600 / (0.600 + 0.090) 8.07

     T_{f} = 7.02 ° C

4 0
3 years ago
What changes a ball velocity
Grace [21]

Answer/Explanation: Speed and direction can change with time. When you throw a ball into the air, it leaves your hand at a certain speed. As the ball rises, it slows down. Then, as the ball falls back toward the ground, it speeds up again. When the ball hits the ground, its direction of motion changes and it bounces back up into the air.

5 0
4 years ago
What is the kinetic energy of a 1.40 kg discus with a speed of 22.5 m/s?
Oksana_A [137]
Kinetic energy = (1/2) (mass) (speed)²

                         = (1/2) (1.4 kg) (22.5 m/s)²

                         =    (0.7 kg)  (506.25 m²/s² )

                         =          354.375  kg-m²/s²  =  354.375 joules .

This is just the kinetic energy associated with a 1.4-kg glob of
mass sailing through space at 22.5 m/s.  In the case of a frisbee,
it's also spinning, and there's some additional kinetic energy stored
in the spin. 
8 0
3 years ago
A circular coil with 600 turns has a radius of 15 cm. The coil is rotating about an axis perpendicular to a magnetic field of 0.
Reil [10]

Answer:

The angular frequency is the coil rotating is 1.9 rad/s.

Explanation:

Given that,

Number of turns = 600

Radius = 15 cm

Magnetic field = 0.020 T

Maximum induced emf = 1.6 V

We need to calculate the angular frequency is the coil rotating

Using formula emf

\epsilon =NBA\omega\sin\omega t

When  induced emf is maximum so \sin\omega t will be 1.

\omega=\dfrac{\epsilon}{NBA}

Where, N = number of turns

A = area

B = magnetic field

Put the value into the formula

\omega=\dfrac{1.6}{600\times\pi\times(15\times10^{-2})^2\times0.020}

\omega=1.9\ rad/s

Hence, The angular frequency is the coil rotating is 1.9 rad/s.

6 0
3 years ago
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