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Dahasolnce [82]
2 years ago
12

A charged particle is placed in an external magnetic field and it is moving in a circular path of radius 26m.The magnetic force

acting on the particle is 16N.What is the kinetic energy of the particle
Physics
1 answer:
ElenaW [278]2 years ago
4 0

Answer:

208 Joules

Explanation:

The radius of the circular path the charge moves, r = 26 m

The magnetic force acting on the charge particle, F = 16 N

Centripetal force, F_c = m·v²/r

Kinetic energy, K.E. = (1/2)·m·v²

Where;

m = The mass of the charged particle

v = The velocity of the charged particle

r = The radius of the path of the charged particle

Whereby the magnetic force acting on the charge particle = The centripetal force, we have;

F = F_c = m·v²/r = 16 N

(1/2) × r × F_c = (1/2) × r × m·v²/r = (1/2)·m·v² = K.E.

∴ (1/2) × r × F_c = (1/2) × 26 m × 16 N =  = (1/2)·m·v² = K.E.

∴ 208 Joules = K.E.

The kinetic energy of an particle moving in the circular path, K.E. = 208 Joules.

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The escape velocity is defined to be the minimum speed with which an object of mass m must move to escape from the gravitational
s344n2d4d5 [400]

Answer:

v = √2G M_{earth} / R

Explanation:

For this problem we use energy conservation, the energy initiated is potential and kinetic and the final energy is only potential (infinite r)

        Eo = K + U = ½ m1 v² - G m1 m2 / r1

        Ef = - G m1 m2 / r2

When the body is at a distance R> Re, for the furthest point (r2) let's call it Rinf

       Eo = Ef

       ½ m1v² - G m1 M_{earth} / R = - G m1 M_{earth} / R

      v² = 2G M_{earth} (1 / R - 1 / Rinf)

If we do Rinf = infinity     1 / Rinf = 0

       v = √2G M_{earth} / R

      Ef = = - G m1 m2 / R

The mechanical energy is conserved  

 

      Em = -G m1  M_{earth} / R

      Em = - G m1  M_{earth} / R

     R = int        ⇒  Em = 0

6 0
2 years ago
In a coiled spring, the particles of the medium vibrate to and fro about their
Kitty [74]

Answer:

In a coiled spring, the particles of the medium vibrate to and fro about their mean positions at an angle of

A. 0° to the direction of propagation of wave

Explanation:

The waveform of a coiled spring is a longitudinal wave, which is made up of vibrations of the spring which are in the same direction as the direction of the wave's advancement

As the coiled spring experiences a compression force and is then released, it experiences a sequential movement of the wave of the compression that extends the length of the coiled spring which is then followed by a stretched section of the coiled spring in a repeatedly such that the direction of vibration of particles of the coiled is parallel to direction of motion of the wave

From which we have that the angle between the direction of vibration of the particles of the coiled spring and the direction of propagation of the wave is 0°.

8 0
2 years ago
Which is not an example of a force?
NNADVOKAT [17]

Answer:

possibly A?

Explanation:

just feels right man

7 0
2 years ago
Please help!!!!!!!!!​
Elena-2011 [213]

Answer:

v = 12.86 km/h

v = 3.6 m/s

Explanation:

Given,

The distance, d = 13.5 km

The time, t = 21/20 h

                  =  1.05 h

The velocity of a body is defined as the distance traveled by the time taken.

                                     v = d / t

                                        =  13.5 km / 1.05 h

                                        = 12.86 km/h

The conversion of km/h to m/s

                                   1 km/h = 0.28 m/s

                                     12.86 km/h = 12.86 x 0.28 m/s

                                                         = 3.6 m/s

Hence, the velocity in m/s is, v = 3.6 m/s

7 0
3 years ago
I need help quickly pls
sukhopar [10]

Answer:

Ok I'm not 100% on this one but, try 3 lifes sorry if u get it wrong D:

Explanation:

4 0
2 years ago
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