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3 years ago

Can someone explain why the rangers are doing so bad this year

Chemistry

1 answer:

zheka24 [161]3 years ago

7 0

Answer: because they are not working hard enough

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How many grams of sodium bromide are in 500 grams of solution that is 30% sodium bromide by mass?

VARVARA [1.3K]

150g

Explanation:

Mass of solution = 500g

Percentage by mass of NaBr = 30%

Unknown:

Mass of NaBr in the solution = ?

Solution:

A solution is a homogeneous mixture made up of solutes dissolved in a solvent.

The solute is usually the substance that is solvable in another.

When a substance in another, it contains that amount per volume of the whole solution.

Now the mass of solution is 500g

Concentration = Percentage of NaBr in it = 30%

The mass of NaBr = percentage of NaBr x mass of solution

Mass of NaBr = $\frac{30}{100}$ x 500 = 150g

learn more:

Molarity brainly.com/question/9324116

#learnwithBrainly

7 0

3 years ago

Is "isotope" another name for an atom??

GuDViN [60]

An Isotope is when an element has the same number of protons but different number of neutrons. its the same element but the masses(protons+neutrons) are different

5 0

3 years ago

Read 2 more answers

What is the pH of a 1 x 10–4 M HCl solution?

zhenek [66]

Answer:

0001 M HCl is the same as saying that 1 *10-4 moles of H+ ions have been added to solution. The -log[. 0001] =4, so the pH of the solution =4

3 0

3 years ago

In the laboratory a general chemistry student finds that when 2.84 g of KClO4(s) are dissolved in 107.70 g of water, the tempera

vredina [299]

Answer : The enthalpy change of dissolution of $KClO_4$ is 54.3 kJ/mole

Explanation :

Heat released by the reaction = Heat absorbed by the calorimeter + Heat absorbed by the water

$q=[q_1+q_2]$

$q=[c_1\times \Delta T+m_2\times c_2\times \Delta T]$

where,

q = heat released by the reaction

$q_1$ = heat absorbed by the calorimeter

$q_2$ = heat absorbed by the water

$c_1$ = specific heat of calorimeter = $1.55J/^oC$

$c_2$ = specific heat of water = $4.184J/g^oC$

$m_2$ = mass of water = 107.70 g

$\Delta T$ = change in temperature = $T_2-T_1=(22.80-20.34)=2.46^oC$

Now put all the given values in the above formula, we get:

$q=[(1.55J/^oC\times 2.46^oC)+(107.70g\times 4.184J/g^oC\times 2.46^oC)]$

$q=1112.3J=1.1123kJ$

Now we have to calculate the enthalpy change of dissolution of $KClO_4$

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy change = ?

q = heat released = 1.1123 kJ

m = mass of $KClO_4$ = 2.84 g

Molar mass of $KClO_4$ = 138.55 g/mol

$\text{Moles of }KClO_4=\frac{\text{Mass of }KClO_4}{\text{Molar mass of }KClO_4}=\frac{2.84g}{138.55g/mole}=0.0205mole$

$\Delta H=\frac{1.1123kJ}{0.0205mole}=54.3kJ/mole$

Therefore, the enthalpy change of dissolution of $KClO_4$ is 54.3 kJ/mole

5 0

4 years ago

why do astronomers use frequencies other than the visible ones when they are investigating the universe?

Aneli [31]

Because different objects give out electromagnetic radiation at different frequencies. Some objects are very ea...

Hope this help

4 0

3 years ago

Can someone explain why the rangers are doing so bad this year​

Can someone explain why the rangers are doing so bad this year