C(p) = 1.065(7.50p) + 20.25
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We have that the original pressure of this gas is mathematically given as
P2=17.854 kPa
<h3>Boyle's law</h3>Question Parameters:
AT constant temperature, a gas is compressed from 5.5 L to 1 L.
At 1 L, the pressure of the gas is 98.2 kPa
Generally the equation for Boyle's law is mathematically given as
P1V1=P2V2
Therefore
P2=17.854 kPa
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