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Sedaia [141]
3 years ago
14

George and Harriot walk with an average velocity of .95 m/s eastward. If it takes them 30

Physics
2 answers:
lara [203]3 years ago
8 0

Answer:

1.71km

Explanation

Velocity is defined as the change in displacement of a body with respect to time. Displacement specifies direction and as such is a vector quantity.

Mathematically;

Velocity = displacement/time

Displacement = velocity ×time

Given velocity of the body = 0.95m/s

Time = 30minutes

Time = (30×60)seconds

= 1800seconds

Displacement = 0.95×1800

Displacement = 1710m

Since 1000m = 1km

1710m to km will give;

1710/1000

= 1.71km

artcher [175]3 years ago
5 0

Answer:

1.71 km

Explanation:

Convert 30 minutes to seconds:

30 min × (60 s / min) = 1800 s

Find the displacement:

0.95 m/s × 1800 s = 1710 m

Convert to kilometers:

1710 m × (1 km / 1000 m) = 1.71 km

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Answer:

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How many hydrogens are in 3 molecules of H20?
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Choose the sentence that might be found in a personal narrative that correctly uses both a gerund and an infinitive.
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3 0
3 years ago
Oil having a density of 926 kg/m3 floats on water. A rectangular block of wood 3.69 cm high and with a density of 974 kg/m3 floa
zloy xaker [14]

Answer:

the position of the wood below the interface of the two liquids is 2.39 cm.

Explanation:

Given;

density of oil, \rho _o = 926 kg/m³

density of the wood, \rho _{wood} = 974 kg/m³

density of water, \rho _w = 1000 kg/m³

height of the wood, h = 3.69 cm

Based on the density of the wood, it will position across the two liquids.

let the position of the wood below the interface of the two liquids = x

Let the wood be in equilibrium position;

F_{wood} - F_{oil} - F_{water} = 0\\\\\rho _{wood} .gh - \rho _o .g(h-x) - \rho_w .gx = 0\\\\\rho _{wood} .h - \rho _o (h-x) - \rho_w .x = 0\\\\\rho _{wood} .h -\rho _o h + \rho _o x - \rho_w .x =0\\\\h (\rho _{wood}  -\rho _o ) = x( \rho_w - \rho _o)\\\\x =h[\frac{ \rho _{wood}  -\rho _o }{\rho_w - \rho _o} ]\\\\x = 3.69\ cm \times [\frac{974 - 926}{1000-926} ]\\\\x = 2.39 \ cm

Therefore, the position of the wood below the interface of the two liquids is 2.39 cm.

6 0
3 years ago
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