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3 years ago

6

Is it polar or non-polar... i need help on all of them plz hurry

1 answer:

Murljashka [212]3 years ago

5 0

Answers

1.) non-polar

2.) non-polar

3.) Polar

4.) Polar

Non-polar molecules are essentially molecules that have an even distribution of of electrical charges.

Polar molecules is the separation of electric charges, having one positive end and another negative end.

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The floor of a railroad flatcar is loaded with loose crates having a coefficient of static friction of 0.420 with the floor. If

bonufazy [111]

Answer:

The distance is $s= 30.3 \ m$

Explanation:

From the question we are told that

The coefficient of static friction is $\mu_s = 0.42$

The initial speed of the train is $u = 57 \ km /hr = 15.8 \ m/s$

For the crate not to slide the friction force must be equal to the force acting on the train i.e

$-F_f = F$

The negative sign shows that the two forces are acting in opposite direction

=> $mg * \mu_s = ma$

=> $-g * \mu_s = a$

=> $a = -9.8 * 0.420$

=> $a = -4.116 m/s^2$

From equation of motion

$v^2 = u^2 + 2as$

Here v = 0 m/s since it came to a stop

=> $s= \frac{v^2 - u^2 }{ 2 a}$

=> $s= \frac{0 -(15.8)^2 }{ - 2 * 4.116}$

=> $s= 30.3 \ m$

7 0

3 years ago

A real heat engine operates between temperatures tc and th. during a certain time, an amount qc of heat is released to the cold

tino4ka555 [31]

$q_{c}$ = Heat released to cold reservoir

$q_{h}$ = Heat released to hot reservoir

$W_{max}$ = maximum amount of work

$t_{c}$ = temperature of cold reservoir

$t_{h}$ = temperature of hot reservoir

we know that

$\frac{q_{c}}{q_{h}}=\frac{t_{c}}{t_{h}}$

$q_{h} = (\frac{t_{h}}{t_{c}})q_{c}$ eq-1

maximum work is given as

$W_{max}$ = $q_{h}$ - $q_{c}$

using eq-1

$W_{max}$ = $(\frac{t_{h}}{t_{c}})q_{c}$ - $q_{c}$

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3 years ago

A rope has one end tied to a vertical support. You hold the other end so that the rope is horizontal. If you move the end of the

Strike441 [17]

Answer:

c. 2 m/s

Explanation:

The relationship between speed, frequency and wavelength of a wave is given by:

$v=f \lambda$

where

v is the speed of the wave

f is its frequency

$\lambda$ is the wavelength

For the transverse wave in this problem, we have:

$f = 4 Hz$ is the frequency

$\lambda=0.5 m$ is the wavelength

Substituting these numbers into the equation, we find the speed of the wave:

$v=(4 Hz)(0.5 m)=2 m/s$

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gavmur [86]

True! All sounds come from some type of vibrating object. Hopefully I helped!

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Marianna [84]

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