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jonny [76]
3 years ago
9

The base-dissociation constant, kb, for pyridine, c5h5n, is 1.4x10-9 the acid-dissociation constant, ka, for the pyridinium ion,

(pyridine's conjugate acid, is __________.
Chemistry
1 answer:
sp2606 [1]3 years ago
5 0
We are given the base dissociation constant, Kb, for Pyridine (C5H5N) which is 1.4x10^-9. The acid dissociation constant, Ka for the Pyridium ion or the conjugate acid of Pyridine is to be determined. We know from our chemistry classes that:

Kw = Kb * Ka

where Kw is always equal to 1x10^-14

so, to solve for Ka of Pyridium ion, substitute Kb to the equation together with Kw and solve for Ka:

1x10^-14 = 1.4x10^-9 * Ka
solve for Ka

Ka = 7.14x10^-6 

Therefore, the acid dissociation constant of Pyridinium ion is 7.14x10^-6.
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A polar covalent bond will form between which two atoms?
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If, Electronegativity difference is,

 

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For Be and F,

                    E.N of Fluorine          =   3.98

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For H and Cl,

                    E.N of Chorine           =   3.16

                    E.N of Hydrogen        =   2.20

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For Na and O,

                    E.N of Oxygen          =   3.44

                    E.N of Sodium          =   0.93

                                                       ________

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For F and F,

                    E.N of Fluorine          =   3.98

                    E.N of Fluorine          =   3.98

                                                        ________

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Result:

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Q = 25,06 kJ.

Explanation:

6 0
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