Answer:
The amount of HC₂H3₃2(aq) in the flask after the addition of 5.0mL of NaOH(aq) compared to the amount of HC₂H₃O₂(aq) in the flask after the addition of 1.0mL is much smaller because more HC₂H₃O₂(aq) is required to react with 5.0 mL NaOH than with 1.0 mL NaOH.
Explanation:
Equation of the reaction between acetic acid, HC₂H₃O₂(aq) and sodium hydroxide, NaOH(aq) is given below:
CH₃COOH (aq) + NaOH (aq) ----> CH₃COONa (aq) + H₂O
The equation of the reaction shows that acetic acid andsodium hydroxide will react in a 1:1 ratio
Since the concentration of NaOH was not given, we can assume that the concentration is 0.01 M
Moles of NaOH in 5.0 mL of 0.01 M NaOH = 0.01 × 5/1000 = 0.00005 moles
Moles of NaOH in 1.0 mL of 0.01 M NaOH = 0.01 ×1/1000 = 0.0001 moles
Ratio of moles of NaOH in 5.0 mL to 1.0 mL = 0.00005/0.00001 = 5
There are five times more moles of NaOH in 5.0 mL than in 1.0 mL and this means that 5 times more the quantity of HC₂H₃O2(aq) required to react with 1.0 mL NaoH is needed to react with 5.0 mL NaOH.
Therefore, the amount of HC₂H₃O2(aq) in the flask after the addition of 5.0mL of NaOH(aq) compared to the amount of HC₂H₃O₂(aq) in the flask after the addition of 1.0mL is much smaller because more HC₂H₃O₂(aq) is required to react with 5.0 mL NaOH than with 1.0 mL NaOH.
I hope this helps answer some of your questions.
Answer is: pH value of morphine is 10.64.<span>
Chemical reaction: </span>C₁₇H₁₉NO₃ + H₂O → C₁₇H₁₉NO₃H⁺ +OH⁻.<span>
Kb(</span>C₁₇H₁₉NO₃) = 10∧(-5,79) = 1,62·10⁻⁶.<span>
c(</span>C₁₇H₁₉NO₃<span>) = 0,115 M.</span><span>
Kb(</span>C₁₇H₁₉NO₃) = c(OH⁻) · c(C₁₇H₁₉NO₃H⁺) ÷ c(C₁₇H₁₉NO₃).<span>
c(OH</span>⁻)
= c(C₁₇H₁₉NO₃H⁺) = x.
1,62·10⁻⁶<span> = x² ÷
(0,115 - x).</span><span>
Solve quadratic equation: x = c(OH</span><span>⁻) = </span><span>0,000431 M.
pOH = -log(</span>0,000431 M<span>) = 3,36.
pH = 14 - 3,36 = 10,64.</span>
The answer is b. as a whole, the species is mutually beneficial to carry on each others traits and exist in the same ecosystem.
