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IgorLugansk [536]
4 years ago
13

A plane takes off at an angle of elevation of 15 and travels in a straight line for 3,000 meters. What is the height of the plan

e above the ground at this instant?
Mathematics
1 answer:
Gala2k [10]4 years ago
3 0

That's a right triangle with hypotenuse 3000 and the height y is the side opposite the elevation angle of 15 degrees.

y = 3000 \sin 15^\circ


We can actually compute \sin 15^\circ exactly but I won't bother.

y \approx 776 \textrm{ feet}

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