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creativ13 [48]
3 years ago
7

A tank contains 15.6 litres of water when it is 1/6 full.What is its full capacity?

Mathematics
2 answers:
Andreas93 [3]3 years ago
5 0

The answer is 93.6 Hope it helps :)

ollegr [7]3 years ago
4 0

do 15.6 times 6. If 15.6 is 1/6 you do 15.6 times 6.

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Consider the half of the sphere of radius 2 centered at the origin which lies above the xy-plane (a hemisphere). Suppose the den
Harlamova29_29 [7]

Answer:

25.133 units

Step-by-step explanation:

Since the density ρ = r, our mass is

m =  ∫∫∫r³sinθdΦdrdθ. We integrate from θ = 0 to π (since it is a hemisphere), Φ = 0 to 2π and r = 0 to 2  and  the maximum values of r = 2 in those directions. So

m =∫∫[∫r³sinθdΦ]drdθ      

m = ∫[∫2πr³sinθdθ]dr     ∫dФ = 2π

m = ∫2πr³∫sinθdθ]dr

m = 2π∫r³dr    ∫sinθdθ = 1

m = 2π × 4     ∫r³dr = 4

m = 8π units

m = 25.133 units

5 0
3 years ago
What's 926484848+37863249098765775=
Kruka [31]
Its 37863258361430 man that was a lol to type!
5 0
3 years ago
Please help me with this!
Reil [10]

Answer:

11^5 and 11 * 11 * 11 * 11 * 11

Step-by-step explanation:

They are the same thing. Both are multiplying eleven 5 times.

5 0
3 years ago
On a number line, what is the distance between -0.6 to -0.4?
Mila [183]
Answer is B
-0.6- (-0.4)= -0.6+0.4= -0.2
4 0
3 years ago
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Consider a circle whose equation is x2 + y2 + 4x – 6y – 36 = 0. Which statements are true? Check all that apply. To begin conver
umka21 [38]

Answer:

1) False, to begin converting the equation to standard form, each side must be added by 36. 2) True, to complete the square for the x terms, add 4 to both sides, 3) True, the center of the circle is at (-2, 3), 4) False, the center of the circle is at (-2, 3), 5) False, the radius of the circle is 7 units, 6) False, the radius of the circle is 7 units.

Step-by-step explanation:

Let prove the validity of each choice:

1) To begin converting the equation to standard form, subtract 36 from both sides:

Let consider the following formula and perform the following algebraic operations:

(i) x^{2} + y^{2} + 4\cdot x - 6\cdot y  - 36 = 0 Given

(ii) x^{2} + 4\cdot x + y^{2} - 6\cdot y - 36 = 0 Commutative Property

(iii) (x^{2} + 4\cdot x + 4) - 4 + (y^{2} - 6\cdot y + 9) - 9 -36 = 0 Modulative/Associative Property/Additive Inverse Existence

(iv) (x+ 2)^{2} - 4 + (y - 3)^{2} - 9 - 36 = 0  Perfect Trinomial Square

(v) (x+2)^{2} +(y-3)^{2} = 4 + 9 + 36 Commutative Property/Compatibility with Addition/Additive Inverse Existence/Modulative Property

(vi) (x+2)^{2} + (y-3)^{2} = 49 Definition of Addition/Result

False, to begin converting the equation to standard form, each side must be added by 36.

2) True, step (iii) on exercise 1) indicates that both side must be added by 4.

3) The general equation for a circle centered at (h, k) is of the form:

(x-h)^{2}+ (y-k)^{2} = r^{2}

Where r is the radius of the circle.

By direct comparison, it is evident that circle is centered at (-2,3).

True, step (vi) on exercise 1) indicates that center of the circle is at (-2, 3).

4) False, step (vi) on exercise 1) indicates that the center of the circle is at (-2, 3), not in (4, -6).

5) After comparing both formulas, it is evident that radius of the circle is 7 units.

False, the radius of the circle is 7 units.

6) After comparing both formulas, it is evident that radius of the circle is 7 units.

False, the radius of the circle is 7 units.

5 0
3 years ago
Read 2 more answers
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