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Aleksandr-060686 [28]
3 years ago
12

What is the pH of a solution that has a hydronium ion concentration 100 times less than a solution with a pH of 6 explain your r

easoning?
Chemistry
1 answer:
aksik [14]3 years ago
4 0

Answer:

4

Explanation:

cuz i just took a test and the question was this just reversed. if the ph is 4 and the other ph is 100x greater it’s 6. i don’t kno the reasoning lol

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Which statement describes the 3d, 4s, and 4p orbitals of Arsenic (As) based on its electronic configuration and position in the
tekilochka [14]

Answer:

The 3d and 4s orbitals are completely filled, and the 4p orbital is partially filled.

Explanation:

8 0
3 years ago
9. Suppose that 25.0 mL of a gas at 725 mm Hg and 20°C is converted to standard
storchak [24]

Answer:

V₂ = 22.23 mL

Explanation:

According to general gas equation:

P₁V₁/T₁ = P₂V₂/T₂

Given data:

Initial volume = 25 mL

Initial pressure = 725 mmHg (725/760 =0.954 atm)

Initial temperature = 20 °C (20 +273 = 293 K)

Final pressure = standard = 1 atm

Final temperature = standard = 273.15 K

Final volume = ?

Solution:

P₁V₁/T₁ = P₂V₂/T₂

V₂ = P₁V₁ T₂/ T₁  P₂

V₂ = 0.954 atm × 25 mL × 273.15 K / 293 K × 1 atm

V₂ =  6514.63 mL . atm . K  / 293 K . atm

V₂ = 22.23 mL

8 0
3 years ago
Calculate the pH after 10 mL of 1.0 M sodium hydroxide is added to 60 mL of 0.5M acetic acid.
baherus [9]

Explanation:

It is given that the total volume is (10 mL + 60 mL) = 70 mL.

Also, it is known that M_{1}V_{1} = M_{2}V_{2}

Where,    V_{1} = total volume

               V_{2} = initial volume

Therefore, new concentration of CH_{3}COOH = \frac{M_{2}V_{2}}{V_{1}}

                                        = \frac{60 \times 0.5}{70}

                                        = 0.43 M

New concentration of NaOH = \frac{M_{2}V_{2}}{V_{1}}

                                               = \frac{10 \times 1.0}{70}

                                               = 0.14 M

So, the given reaction will be as follows.

              CH_{3}COOH + OH^{-} \rightarrow CH_{3}COO^{-} + H_{2}O

Initial:             0.43          0.14                     0

Change:          -0.14        -0.14                    0.14

Equilibrium:    0.29          0                       0.14

As it is known that value of pK_{a} = 4.74

Therefore, according to Henderson-Hasselbalch equation calculate the pH as follows.

           pH = pK_{a} + log \frac{[CH_{3}COO^{-}]}{[CH_{3}COOH]}

                 = 4.74 + log \frac{0.14}{0.29}

                 = 4.74 + (-0.316)

                 = 4.42

Therefore, we can conclude that the pH of given reaction is 4.42.

6 0
3 years ago
The reaction below demonstrates which characteristic of a base? Upper C U upper S upper O subscript 4 (a q) plus 2 upper N a upp
Gnesinka [82]

"The ability of a base to react with a soluble metal salt" demonstrates characteristic of a base.

<u>Answer:</u> Option D

<u>Explanation:</u>

As the sodium hydroxide react with only with some metals. It is a very strong basic compound with a intense solubility in water and hygroscopic in nature. The ability of base is reflected from its potential to react with metals. In the given reaction:

\mathrm{CuSO}_{4}(a q)+2 \mathrm{NaOH}(a q) \rightarrow \mathrm{Cu}(\mathrm{OH})_{2}(s)+\mathrm{Na}_{2} \mathrm{SO}_{4}(a q)

\mathrm{Cu} \mathrm{SO}_{4} is an acidic property showing salt which is added with sodium hydroxide and this reaction result into a pale blue precipitate of basic copper hydroxide & sodium sulphate which is neutral salt. The reaction is a double displacement and precipitation reaction.

6 0
3 years ago
Read 2 more answers
An adaptation is best described as occurring over which time scale? *
dezoksy [38]

Answer:

over many eras

Explanation:

3 0
2 years ago
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