Answer:
The 3d and 4s orbitals are completely filled, and the 4p orbital is partially filled.
Explanation:
Answer:
V₂ = 22.23 mL
Explanation:
According to general gas equation:
P₁V₁/T₁ = P₂V₂/T₂
Given data:
Initial volume = 25 mL
Initial pressure = 725 mmHg (725/760 =0.954 atm)
Initial temperature = 20 °C (20 +273 = 293 K)
Final pressure = standard = 1 atm
Final temperature = standard = 273.15 K
Final volume = ?
Solution:
P₁V₁/T₁ = P₂V₂/T₂
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 0.954 atm × 25 mL × 273.15 K / 293 K × 1 atm
V₂ = 6514.63 mL . atm . K / 293 K . atm
V₂ = 22.23 mL
Explanation:
It is given that the total volume is (10 mL + 60 mL) = 70 mL.
Also, it is known that
= 
Where,
= total volume
= initial volume
Therefore, new concentration of
= 
= 
= 0.43 M
New concentration of NaOH = 
= 
= 0.14 M
So, the given reaction will be as follows.

Initial: 0.43 0.14 0
Change: -0.14 -0.14 0.14
Equilibrium: 0.29 0 0.14
As it is known that value of
= 4.74
Therefore, according to Henderson-Hasselbalch equation calculate the pH as follows.
pH = ![pK_{a} + log \frac{[CH_{3}COO^{-}]}{[CH_{3}COOH]}](https://tex.z-dn.net/?f=pK_%7Ba%7D%20%2B%20log%20%5Cfrac%7B%5BCH_%7B3%7DCOO%5E%7B-%7D%5D%7D%7B%5BCH_%7B3%7DCOOH%5D%7D)
= 
= 4.74 + (-0.316)
= 4.42
Therefore, we can conclude that the pH of given reaction is 4.42.
"The ability of a base to react with a soluble metal salt" demonstrates characteristic of a base.
<u>Answer:</u> Option D
<u>Explanation:</u>
As the sodium hydroxide react with only with some metals. It is a very strong basic compound with a intense solubility in water and hygroscopic in nature. The ability of base is reflected from its potential to react with metals. In the given reaction:

is an acidic property showing salt which is added with sodium hydroxide and this reaction result into a pale blue precipitate of basic copper hydroxide & sodium sulphate which is neutral salt. The reaction is a double displacement and precipitation reaction.