In order to answer this question, the units of volume must be consistent. In this problem, we decide the unit m3 to be uniform. Option A is equal to 12 m3, option b is equal to 1.2x10^8/100^3 or 120 m3. Option C is 2.0 x10^4/ 10^3 or 20 m3. Option D is 1.2x10^8/ 1000^3 or 0.12 m3. The greatest volume is option b. 120 m3.
The balanced chemical equation is:
2H2 + O2 ---> 2H2O
We are given the amount of the product produced from the reaction. This will be the starting point for the calculations.
355 g H2O ( 1 mol H2O/ 18.02 g H2O) ( 1 mol O2 / 2 mol H2O ) ( 32 g O2 / 1 mol O2 ) = 315.205 g O2
Complete Question
Magnesium sulfate forms a hydrate with the formula 
. What is the maximum amount of water (in grams) that can be removed from 15 ml of toluene by the addition of 200 mg of anhydrous magnesium sulfate? The molar mass of 
is 120.4 g/mol; H20 = 18 g/mol.
Answer:
The value is 
of 
Explanation:
From the question we are told that
The volume of toluene is 
The mass of anhydrous magnesium sulfate is 
The formula of the hydrate is
The molar mass of is 
From the formula given we see that
1 mole of 
wil remove 7 moles of to for the given formula
Hence
120.4 g (1 mole) will remove 7 moles (7 * 18 g = 126 g ) of to for the given formula
Therefore 1 g of x g of
So
![x = \frac{x]126 * 1}{ 120.4 }](https://tex.z-dn.net/?f=x%20%20%3D%20%20%5Cfrac%7Bx%5D126%20%2A%20%201%7D%7B%20120.4%20%7D)
=> 
From our calculation we obtained that
1 g of will remove of
Then
of will remove z g of of
So
=>
=> of
Answer:
oxygen
Explanation:
I am pretty sure it is that but you should still check
