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Delvig [45]
3 years ago
8

Nitrogen dioxide and water react to produce nitric acid, HNO3,

Chemistry
1 answer:
maw [93]3 years ago
7 0

Answer:

Explanation:

a )

3NO₂(g) + H₂O(l) — -→ 2HNO₃(aq) + NO(g)

3 x 46 g       18 g            2 x 63 g       30 g

138 g of NO₂ requires 18 g of H₂O

28 g of NO₂ requires ( 18 / 138) x 28

= 3.65 g of H₂O.

b )

18 g of H₂O produces 30 g of NO gas

15.8 g of H₂O produces ( 30/18 ) x 15.8

= 26.33 g of NO gas .

c )

138 g of NO₂ produces 126 g of HNO₃

8.25 g  of NO₂ produces (126 / 138 ) x 8.25

= 7.53 g of HNO₃

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Answer:

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Explanation:

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Consider the reaction 2SO2(g) O2(g) Right arrow. 2SO3(g). Substance Delta. Hf (kJ/mol) S (J/(molmc021-3. JpgK)) SO3(g) –396 130.
7nadin3 [17]

The reaction has \Delta G value of -296 kJ/mol, and the reaction is spontaneous. Hence, option A is correct.

The value of \Delta G for the reaction is the change in the free energy. The \Delta G for the reaction is calculated as:

\Delta G=\Delta H-T\Delta S

<h3>Computation for \Delta G of the reaction</h3>

The given reaction is:
\rm 2\;SO_2\;+\;O_2\;\to\;2\;SO_3

The change in enthalpy and entropy is given by the difference in product and reactant.

Thus, the change in free energy is given as:

\Delta G=(\Delta H_{product}-\Delta H_{reactant})-T(\Delta S_{product}-\Delta S_{reactant})\\\\\Delta G=(2(\Delta H_{SO_3})-(2(\Delta H_{SO_2})\;+\;\Delta S_{O_2}))-T((2(\Delta S_{SO_3})-(2(\Delta S_{SO_2}))

Substituting the values in the above equation at a temperature of 300 K.

\Delta G=(2(-396)-(2(-297)\;+\;(0)))-300\;(2(130.58)-(2(191.50)+(205)))\\\Delta G=(-792-(-1386))-300\;(261.16+588)\\\Delta G=-296\; \rm kJ/mol

The negative value of \Delta G represents the reaction to be spontaneous.

Thus, the reaction has \Delta G value of -296 kJ/mol, and the reaction is spontaneous. Hence, option A is correct.

Learn more about free energy, here:

brainly.com/question/14143095

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