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kati45 [8]
3 years ago
14

How do the melting and boiling points of pure water differ from those of a sugar-water solution?

Chemistry
2 answers:
belka [17]3 years ago
8 0

For pure water, the boiling point is 100 degrees Celsius (212 Fahrenheit) at one atmosphere of pressure, and the melting point is 0 degrees Celsius (32 degrees Fahrenheit) at one atmosphere of pressure. At  at high altitudes the lower pressure makes the boiling point several degrees lower. For example, in Denver, Colorado, the boiling point is about 95°C or 203°F.

Vesnalui [34]3 years ago
6 0

When a solute, sugar in this case, is added, the boiling point of the solution increases. Additionally, the melting point decreases.

To answer your question,

The boiling point of pure water is lower than sugar-water solution.

The melting point is higher for pure water than for sugar-water solution.


If this helped you, please list me as brainliest!

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A gas has a volume of 450. mL at 55.0 °C. If the volume changes to 502 ml, what is the new temperature?
salantis [7]

Answer:

92.9 °C

Explanation:

Step 1: Given data

  • Initial volume (V₁): 450. mL
  • Initial temperature (T₁): 55.0 °C
  • Final volume (V₂): 502 mL

Step 2: Convert 55.0 °C to Kelvin

We will use the following expression.

K = °C + 273.15 = 55.0 + 273.15 = 328.2 K

Step 3: Calculate the final temperature of the gas

If we assume constant pressure and ideal behavior, we can calculate the final temperature of the gas using Charles' law.

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T₂ = 328.2 K × 502 mL/450. mL = 366 K = 92.9 °C

7 0
3 years ago
g Identify limiting reactants (mole ratio method). Close Problem Identify the limiting reactant in the reaction of bromine and c
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Answer:

(i) Cl₂ is a limiting reactant

(ii) The amount of excess reactant = 4.8 g

Explanation:

                             Br₂(g) + Cl₂(g) → 2 BrCl(g) ---------------------------(i)

Calculation of no. of moles

                            Moles of Br_{2}  = \frac{weight}{Molecular weight} = \frac{29.7}{160} =0.18

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Using mole ratio method to find the limiting reactant and Excess reactant.

                            \frac{Mole}{Stoichiometry} (for Br_{2} ) = \frac{0.18}{1}  = 0.18

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So Cl_{2} is a limiting reactant and Br₂ is excess reactant.

The amount of excess reactant = 0.18 - 0.15 = 0.03 mole = 4.8 g

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4 years ago
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Answer:

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<em>Feel free to mark this as brainliest :D</em>

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