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2 years ago

How many moles of sodium hydrogen carbonate are present in 2.61 grams of this compound?

Chemistry

1 answer:

Sloan [31]2 years ago

7 0

Molar mass of NaHCO_3

23+1+12+3(16)
36+48
84g/mol

Now

$\\ \sf\longrightarrow No\:of\:moles=\dfrac{Given\:mass}{Molar\:mass}$

$\\ \sf\longrightarrow No\:of\; moles=\dfrac{2.61}{84}$

$\\ \sf\longrightarrow No\:of\:moles=0.0312mol$

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Answer:

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3 years ago

the reaction AB2C (g) <---> B2 (g) + AC (g) reached equilibrium at 900 K in a 5.00 L vessel. At equilibrium 0.0840 mol of

Verizon [17]

Answer:

k = 4,92x10⁻³

Explanation:

For the reaction:

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[AB₂C]: 0,0840mol / 5L = 0,0168M

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Replacing this values in (1):

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I hope it helps!

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3 years ago

Significant Figures For 7.06 × 10^5 ÷ 5.3 × 10^-2

Kay [80]

Answer:

$\boxed{\text{two}}$

Explanation:

In multiplication and division problems, your answer can have no more significant figures than the number with the fewest significant figures.

$\dfrac{7.06 \times 10^{5}}{5.3 \times 10^{-2}}= 1.332 075 472 \times 10^{7}$ (by my calculator)

There are three significant figures in 7.06 and two in 2.3.

You must round to $\boxed{\textbf{two}}$ significant figures and report the answer as 1.3 × 1.0⁷.

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