Question

How many moles of sodium hydrogen carbonate are present in 2.61 grams of this compound?

Answer 1

Molar mass of NaHCO_3

• 23+1+12+3(16)
• 36+48
• 84g/mol

Now

$\\ \sf\longrightarrow No\:of\:moles=\dfrac{Given\:mass}{Molar\:mass}$

$\\ \sf\longrightarrow No\:of\; moles=\dfrac{2.61}{84}$

$\\ \sf\longrightarrow No\:of\:moles=0.0312mol$