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2 years ago

How many moles of sodium hydrogen carbonate are present in 2.61 grams of this compound?

Chemistry

1 answer:

Sloan [31]2 years ago

7 0

Molar mass of NaHCO_3

23+1+12+3(16)
36+48
84g/mol

Now

$\\ \sf\longrightarrow No\:of\:moles=\dfrac{Given\:mass}{Molar\:mass}$

$\\ \sf\longrightarrow No\:of\; moles=\dfrac{2.61}{84}$

$\\ \sf\longrightarrow No\:of\:moles=0.0312mol$

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Answer:

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Explanation:

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Energy of the electron in n=1,

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Energy of the electron in n = ∞

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$I.E=3.488\times 10^{-20} kJ$

To convert in into kj/mol multiply it with $N_A=6.022\times 10^{23} mol^{-1}$

$I.E=3.488\times 10^{-20} kJ\times 6.022\times 10^{23} mol^{-1}=21,004.73kJ/mol$

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