<span>Displaced volume :
final volume - initial volume
32.4 mL - 25.2 mL => 7.2 mL
Density = mass / volume
D = 22.6 g / 7.2 mL
D = 3.1388 g/mL
hope this helps!</span>
Mole ratio :
<span>5 C</span>₆<span>H</span>₆<span>CHO + 2 KMnO</span>₄<span> + 6 H</span>⁺ <span>= 5 C</span>₆<span>H</span>₆<span>COOH + 2 Mn</span>²⁺<span> + 3 H</span>₂<span>O + 2 K</span>⁺
5 moles C₆H₆CHO ------------------ 2 moles KMnO₄
1.0 moles C₆H₆CHO ---------------- ( moles of KMnO₄ )
moles of KMnO₄ = 1.0 x 2 / 5
moles of KMnO₄ = 2 / 5
= 0.40 moles of KMnO4
hope this helps!
E has indeed the lowest freezing point.
Answer:
0.33 mol/ L
Explanation:
Please see the step-by-step solution in the picture attached below.
Hope this answer will help you. Have a nice day !
2.5 % w/v ( that means we have 2.5 grams of solute in 100 mL <span>solution )
1.00 mL = 1000 mL therefore:
2.5 g ------------- 100 mL
?? --------------- 1000 mL
1000 x 2.5 / 100 => 25.0 g of NaCl</span>
