Answer:
The amount of current that must flow through the wire for it to be suspended against gravity by magnetic force = 6.125 A
Explanation:
Force on a wire carrying current in an electric field is given by
F = (B)(I)(L) sin θ
For this question,
The magnetic force must match the weight of the wire.
F = mg
mg = (B)(I)(L) sin θ
(m/L)g = (B)(I) sin θ
Mass per unit length = 75 g/m = 0.075 kg/m
B = magnetic field = 0.12 T
I = ?
g = acceleration due to gravity = 9.8 m/s
θ = angle between wire's current direction and magnetic field = 90°
0.075 × 9.8 = 0.12 × I sin 90°
I = 0.075 × 9.8/0.12 = 6.125 A
The correct answer is 40.5 Newtons just finished the quiz and 36.5 was incorrect.
Answer:
D)Not enough information
Explanation:
According to Pascal's principle, the pressure exerted on the two pistons is equal:
Pressure is given by the ratio between force F and area A, so we can write
The force exerted on each piston is just equal to the weight of the corresponding mass: 
, where m is the mass and g is the gravitational acceleration. So the equation becomes
Now we can rewrite the mass as the product of volume, V, times density, d:
We also know that 
So we can further re-arrange the equation (and simplify g as well):
We are also told that block B has bigger volume than block A: 
. However, this information is not enough to allow us to say if the fraction on the right is greater than 1 or smaller than 1: therefore, we cannot conclude anything about the densities of the two objects.
Nulceus - recipe book/instruction manual
Mitochondria - Battery
Endoplasmic reticulum - Printer or a pen?
Golgi aparatus - an envelope
Chloroplasts - green rechargable battery
Cell membrane (elastic band (2 to represent the phospholipid bilayer)
Ribosomes - I guess maybe an ink pot as its the material thats used to write
Cell Wall - the paper bag
lysosomes - washing up liquid (breaks down wate food on a dirty plate)
vaculoes - bottle of water
Answer:
The third particle should be at 0.0743 m from the origin on the negative x-axis.
Explanation:
Let's assume that the third charge is on the negative x-axis. So we have:
We know that the electric field is:
Where:
- k is the Coulomb constant
- q is the charge
- r is the distance from the charge to the point
So, we have:
Let's solve it for r(3).
Therefore, the third particle should be at 0.0743 m from the origin on the negative x-axis.
I hope it helps you!
