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3 years ago

What are the reactants in the photosynthesis chemical equation?

Physics

1 answer:

Ber [7]3 years ago

3 0

<h2>Answer:</h2>

The photosynthesis chemical equation states that the reactants

(carbon dioxide, water and sunlight), yield two products, glucose and oxygen gas. The single chemical equation represents the overall process of photosynthesis.

hope this help you!

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A 1 mW laser beam is incident onto a detector. Determine the fractional fluctuation in number of photons intercepted by the dete

Ugo [173]

Answer:

(a) $625 photons$

(b) $625\times 10^{6}photons$

Explanation:

Given that , the power of the laser beam is,

$P=1 mW\\P=1\times 10^{-3} W$

and time is given is,

$t=1\mu s\\t=10^{-6}s$

Now the energy formula for the laser beam is,

$E=P\times t$

Now,

$E=10^{-3}\times 10^{-6} \\E=10^{-9}J$

(a) The value of energy is given,

$E_{1}=10MeV\\E_{1}=10\times 10^{6}\times 1.6\times 10^{-19}J\\ E_{1}=16\times 10^{-13}J$

Now the no of photons's fraction fluctuation is,

$n=\frac{E}{E_{1} }\\ n=\frac{10^{-9} }{16\times 10^{-13} }\\ E_{1}=625 photons$

Therefore the no of photons is $625 photons$ .

(b)The value of energy is given,

$E_{z}=10eV\\E_{z}=16\times 10^{-19}J$

Now the no of photons's fraction fluctuation is,

$n=\frac{E}{E_{z} }\\ n=\frac{10^{-9} }{16\times 10^{-19} }\\n=625\times 10^{6}photons$

Therefore the no of photons is $625\times 10^{6}photons$ .

5 0

3 years ago

An α-particle has a charge of +2e and a mass of 6.64 × 10-27 kg. It is accelerated from rest through a potential difference that

zzz [600]

Answer with Explanation:

We are given that

Charge on alpha particle=q=2 e= $2\times 1.6\times 10^{-19} C$

1 e= $1.6\times 10^{-19} C$

Mass of alpha particle=m= $6.64\times 10^{-27} kg$

Potential difference,V= $1.97\times 10^6 V$

Magnetic field,B=3.49 T

a.Speed of alpha particle=v= $\sqrt{\frac{2 qV}{m}}$

By using the formula

$v=\sqrt{\frac{2\times 2\times 1.6\times 10^{-19}\times 1.97\times 10^6}{6.64\times 10^{-27}}$

$v=1.38\times 10^7 m/s$

b.Magnetic force,F $=qvB=2\times 1.6\times 10^{-19}\times 1.38\times 10^7\times 3.49=1.5\times 10^{-11} N$

F= $1.5\times 10^{-11} N$

c.Radius of circular path, r= $\frac{mv^2}{F}$

$r= \frac{6.64\times 10^{-27}\times (1.38\times 10^7)^2}{1.5\times 10^{-11}}$

r=0.084 m

5 0

3 years ago

Jane plans to fly from Binghamton, New York, to Springfield, Massachusetts, about 280 km due east of Binghamton. She heads due e

aleksklad [387]

Answer:

90m/h N

Explanation:

we consider janes velocity to the positive X axis so Vj=280km/s

and the final position a dot in on the graph r=294km, we find the x and y components:

294*cos(17.8)=280 X+ confirming our theory

294*sin(17.8)=90 Y+ or N and that's the winds' velocity.

5 0

3 years ago

Help!! this makes no sense to me

bulgar [2K]

3 meters i’m pretty sure

8 0

2 years ago

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When a child does not know how to react emotionally to a situation they will observe the emotional expressions of others. This i

Otrada [13]

Answer:

social referencing

6 0

4 years ago