Here is the answer!!!!!!!
Answer:
La frecuencia será la misma en los dos medios, y en el vacio, no varia.
b) Vacío : n = 3,684 10 m 1,33 = 4 900 Å ,3161 10 m 55,1 n
,6 105 10 Hz
3,161 10 m
v 1,93 10 m/s 193548,38 km/s =
1,55
10 3 m/s
n
c
Vidrio v: =
,6 107 10 Hz
3,684 10 m
v 2,25 10 m/s 225 000km/s =
33,1
10 3 m/s
n
c
a
Answer:
the energy when it reaches the ground is equal to the energy when the spring is compressed.
Explanation:
For this comparison let's use the conservation of energy theorem.
Starting point. Compressed spring
Em₀ = K_e = ½ k x²
Final point. When the box hits the ground
Em_f = K = ½ m v²
since friction is zero, energy is conserved
Em₀ = Em_f
1 / 2k x² = ½ m v²
v = 
x
Therefore, the energy when it reaches the ground is equal to the energy when the spring is compressed.
Answer:
1. 57.99V
2. 37.5Hz
3. 0.7072A
4. 82 ohms
5. 5.18x10^-5F
Explanation:
In answer to this question, we have the Standard equation of AC emf to be
V = V0 x sin ωt
We have
V0 = 82V,
ω = 75π
1.
RMS Voltage =
V0/√2 = 82 /√2
= 82/1.414
= 57.99V
2.
ω = 2π* f
75π = 2πf
Frequency,f = 75π/2π
= 235.5/6.28
= 37.5 Hz
3.
RMS current
= Imax/√2
= 1.00/1.414
= 0.7072A
4.
Reactance
= Vrms/ Irms
= 57.99/0.7072
= 81.999
= 82.0 Ω
5.
Reactance = 1/ ω x C
Reactance = 82
ω = 75π
We put these values into the equation above and make c the subject of the formula
C = 1/82.0 x 75π
C = 1/ 82.0 x 75 x 3.14
C = 1/19311
Capacitance = 5.18x10^-5F
Downstream, the current is helping the swimmer go faster relative to the land
