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sp2606 [1]
3 years ago
11

What is the standard metric unit of power

Physics
1 answer:
mash [69]3 years ago
4 0

[ Power ]  =  [ energy ] / [ time ]

SI unit of energy = Joule
SI unit of time = second

Unit of power  =  (1 joule) / (1 second)  =  1 <em>watt</em>


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Which wavelength produces fluorescence? Why do you think this wavelength produces fluorescence while the other does not?
Maurinko [17]

Answer:

Long wavelength

Explanation:

Wavelengths that corresponds to the bands of blue and red are strongly absorbed whereas the wavelengths that lie in the mid-range corresponds to green light that are absorbed weakly.

Fluorescence produced is always directed towards longer wavelengths of the spectra as compared to the corresponding spectra for absorption.

4 0
3 years ago
How much power will it take to move a 50Kg box 10m across a floor that has -50N of Frictional forces in 3 seconds?
likoan [24]

Answer: 83.3 W

Explanation: I think, I’m not sure. If I’m wrong correct me ;)

8 0
3 years ago
A man paddles a canoe at 6 km per hour. If he paddles on a river with a current of 6 km per hour, what is the speed of the canoe
Romashka-Z-Leto [24]

Answer:

If the canoe heads upstream the speed is zero. And directly across the river is  8.48 [km/h] towards southeast

Explanation:

When the canoe moves upstream, it is moving in the opposite direction of the normal river current. Since the velocities are vector (magnitude and direction) we can sum each vector:

Vr = velocity of the river = 6[km/h}

Vc = velocity of the canoe = -6 [km/h]

We take the direction of the river as positive, therefore other velocity in the opposite direction will be negative.

Vt = Vr + Vc = 6 - 6 = 0 [km/h]

For the second question, we need to make a sketch of the canoe and we are watching this movement at a high elevation. So let's say that the canoe is located in point 0 where it is located one of the river's borders.

So we are having one movement to the right (x-direction). And the movement of the river to the south ( - y-direction).

Since the velocities are vector we can sum each vector, so using the Pythagoras theorem we have:

Vt = \sqrt{(6)^{2} +(-6)^{2} } \\Vt=8.48[km/h]

5 0
3 years ago
For a ∆x of 0.1mm, what is ∆px, the uncertainty in the transverse momentum of a photon passing through a slit (where uncertainty
Colt1911 [192]

Answer:

0.53\times 10^{-30}kgms^{-1}

Explanation:

Uncertainty principle say that the position and momentum can not be measured simultaneously except one relation which is described below,

\Delta x\Delta p=\frac{h}{4\pi }

Given that the uncertainty in x is 0.1 mm.

Therefore,

\Delta p=\frac{6.626\times 10^{-34} }{4\times 3.14\times 1\times 10^{-4}m }\\\Delta p=0.53\times 10^{-30}kgms^{-1}

Therefore, uncertainty in the transverse momentum of photon is 0.53\times 10^{-30}kgms^{-1}

6 0
3 years ago
1 point
Yuliya22 [10]
PE= 3kg x 10N/kg x 10m
= 300J
8 0
3 years ago
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