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mr Goodwill [35]
3 years ago
11

You fill two balloons with gas, one with hydrogen and one with carbon dioxide. You hold a match to each balloon. The hydrogen ba

lloon explodes in a small fireball. The carbon dioxide balloon pops where the match burns it, but nothing else happens. How can you explain this?
A. Hydrogen contains chemical energy and carbon dioxide does not.
B. Hydrogen is a reactant and carbon dioxide is a product.
C. The carbon dioxide smothered the match before it could start a fire.
D. The match did not have enough activation energy to light the carbon dioxide.
E. Hydrogen was able to participate in an exergonic reaction and carbon dioxide couldn’t.
Physics
1 answer:
miv72 [106K]3 years ago
4 0

Answer:E. Hydrogen was able to participate in an exergonic reaction and carbon dioxide couldn't

Explanation:

An exergonic reaction releases energy to the environment. The combustion of hydrogen contained in the balloon is a chemical reaction. The reaction can take place because hydrogen combines with oxygen in air, that is, the gas is combustible. CO2 does not support combustion, it does not combine with oxygen in air and it is also denser than air, hence does not participate in the exergonic reaction.

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Explanation:

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X-direction                                     | Y-direction

x=x_o+v_{xo}t ⇒ x=v_{xo}cos(delta)t |

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3 years ago
Which forces are shown on a free body diagram?
notsponge [240]

Answer:

What is a Free Body Diagram?

The free body diagram helps you understand and solve static and dynamic problem involving forces. It is a diagram including all forces acting on a given object without the other object in the system. You need to first understand all the forces acting on the object and then represent these force by arrows in the direction of the force to be drawn.

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3 years ago
How much time does it take for a spinning baseball with an angular speed of 38 rad/s to rotate through 15 degrees
Nadusha1986 [10]

Answer:

the time of motion of the ball is 6.89 ms.

Explanation:

Given;

angular speed, ω = 38 rad/s

angular distance, θ = 15 degrees

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Time of motion is calculated as;

time = \frac{angular \ distance}{angular \ speed} \\\\t= \frac{\theta}{\omega} = \frac{0.2618 \ rad}{38 \ rad/s} \\\\t = 6.89 \ \times 10^{-3} \ s\\\\t = 6.89 \ ms

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3 years ago
The speed of a wave on a violin A string is 288 m/s and on the G string is 128 m/s. The force exerted on the ends of the string
Katyanochek1 [597]

Answer:

\dfrac{\mu_A}{\mu_G}=0.197

Explanation:

given,

Speed of a wave on violin A = 288 m/s

Speed on the G string = 128 m/s

Force at the end of string G  = 110 N

Force at the end of string A = 350 N

the ratio of mass per unit length of the strings (A/G). = ?

speed for string A

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speed for string G

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Assuming force is same in both the string

now,

dividing equation (2)/(1)

\dfrac{v_G}{v_A}=\dfrac{\sqrt{\dfrac{F_G}{\mu_G}}}{\sqrt{\dfrac{F_A}{\mu_A}}}

\dfrac{v_G}{v_A}=\dfrac{\sqrt{\mu_A}}{\sqrt{\mu_G}}

\dfrac{128}{288}=\dfrac{\sqrt{\mu_A}}{\sqrt{\mu_G}}

\dfrac{\mu_A}{\mu_G}=0.197

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