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mr Goodwill [35]
3 years ago
11

You fill two balloons with gas, one with hydrogen and one with carbon dioxide. You hold a match to each balloon. The hydrogen ba

lloon explodes in a small fireball. The carbon dioxide balloon pops where the match burns it, but nothing else happens. How can you explain this?
A. Hydrogen contains chemical energy and carbon dioxide does not.
B. Hydrogen is a reactant and carbon dioxide is a product.
C. The carbon dioxide smothered the match before it could start a fire.
D. The match did not have enough activation energy to light the carbon dioxide.
E. Hydrogen was able to participate in an exergonic reaction and carbon dioxide couldn’t.
Physics
1 answer:
miv72 [106K]3 years ago
4 0

Answer:E. Hydrogen was able to participate in an exergonic reaction and carbon dioxide couldn't

Explanation:

An exergonic reaction releases energy to the environment. The combustion of hydrogen contained in the balloon is a chemical reaction. The reaction can take place because hydrogen combines with oxygen in air, that is, the gas is combustible. CO2 does not support combustion, it does not combine with oxygen in air and it is also denser than air, hence does not participate in the exergonic reaction.

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With constant angular acceleration \alpha, the disk achieves an angular velocity \omega at time t according to

\omega=\alpha t

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\theta=\dfrac12\alpha t^2

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21.0\,\mathrm{rad}=\dfrac12\alpha(1.00\,\mathrm s)^2\implies\alpha=42.0\dfrac{\rm rad}{\mathrm s^2}

b. Under constant acceleration, the average angular velocity is equivalent to

\omega_{\rm avg}=\dfrac{\omega_f+\omega_i}2

where \omega_f and \omega_i are the final and initial angular velocities, respectively. Then

\omega_{\rm avg}=\dfrac{\left(42.0\frac{\rm rad}{\mathrm s^2}\right)(1.00\,\mathrm s)}2=42.0\dfrac{\rm rad}{\rm s}

c. After 1.00 s, the disk has instantaneous angular velocity

\omega=\left(42.0\dfrac{\rm rad}{\mathrm s^2}\right)(1.00\,\mathrm s)=42.0\dfrac{\rm rad}{\rm s}

d. During the next 1.00 s, the disk will start moving with the angular velocity \omega_0 equal to the one found in part (c). Ignoring the 21.0 rad it had rotated in the first 1.00 s interval, the disk will rotate by angle \theta according to

\theta=\omega_0t+\dfrac12\alpha t^2

which would be equal to

\theta=\left(42.0\dfrac{\rm rad}{\rm s}\right)(1.00\,\mathrm s)+\dfrac12\left(42.0\dfrac{\rm rad}{\mathrm s^2}\right)(1.00\,\mathrm s)^2=63.0\,\mathrm{rad}

5 0
4 years ago
Please help i need help i’ll give lots of points
N76 [4]

Answer:

OK so ik this but what is you question?

Explanation:

8 0
3 years ago
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Answer:

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Donde esta la orilla del universo?
irinina [24]

Answer:

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A neutral copper block is polarized as shown in the figure below, due to an electric field made by external charges (notshown).
Fudgin [204]

Answer:

As point B is located inside the copper block so net electric field at point B is j.

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