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3 years ago

What is the purpose of subscripts in chemical formulas

Chemistry

1 answer:

sammy [17]3 years ago

6 0

D. To indicate an element’s proportions within a formula

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if the Celsius temperature of a gas at constant pressure is increased from 10 Celsius to 20 Celsius the volume is

svet-max [94.6K]

Answer:

The volume is increased.

Explanation:

According to <em>Charles' Law</em>, " <em>at constant pressure the volume and temperature of the gas are directly proportional to each other</em>". Mathematically this law is presented as;

V₁ / T₁ = V₂ / T₂ -----(1)

In statement the data given is,

T₁ = 10 °C = 283.15 K ∴ K = 273.15 + °C

T₂ = 20 °C = 293.15 K

So, it is clear that the temperature is being increased hence, we will find an increase in volume. Let us assume that the starting volume is 100 L, so,

V₁ = 100 L

V₂ = Unknown

Now, we will arrange equation 1 for V₂ as,

V₂ = V₁ × T₂ / T₁

Putting values,

V₂ = 100 L × 293.15 K / 283.15 K

V₂ = 103.52 L

Hence, it is proved that by increasing temperature from 10 °C to 20 °C resulted in the increase of Volume from 100 L to 103.52 L.

3 0

2 years ago

In your lab group, you are in investigating the properties of matter. Your teacher gives you several unknown substances to ident

yulyashka [42]

A B and D
Explanation: I got it right on USATP

6 0

2 years ago

Read 2 more answers

Tritium is an isotope of hydrogen (H) that has:

Anika [276]

D. 1 proton and 1 neutron

7 0

3 years ago

Read 2 more answers

Consider the first-order reaction described by the equation At a certain temperature, the rate constant for this reaction is 5.8

zubka84 [21]

<u>Answer:</u> The half life of the reaction is 1190.7 seconds

<u>Explanation:</u>

The equation used to calculate rate constant from given half life for first order kinetics:

$t_{1/2}=\frac{0.693}{k}$

where,

k = rate constant of the reaction = $5.82\times 10^{-4}s^{-1}$

$t_{1/2}$ = half life of the reaction = ?

Putting values in above equation, we get:

$t_{1/2}=\frac{0.693}{5.82\times 10^{-4}s^{-1}}=1190.7s$

Hence, the half life of the reaction is 1190.7 seconds

8 0

3 years ago

At what temperature does 0.019135 moles of Ne in a 878.3 mL container exert a pressure of 0.946 atm?

Reika [66]

<h3>Answer:</h3>

Temperature is 529.164 K

<h3>Explanation:</h3>

We are given

Number of moles of Ne (n) = 0.019135 moles

Volume (V) = 878.3 mL

Pressure (P) = 0.946 atm

We are required to calculate the temperature;

We can do this using the ideal gas law equation which is;

PV = nRT, where P is the pressure, n is the number of moles, V is the volume, R is the ideal gas constant (0.082057 Latm/mol/K) and T is the temperature.

From the equation;

$T=\frac{PV}{nR}$

$T = \frac{(0.946)(0.8783)}{(0.082057)(0.019135)}$

$T=529.164 K$

Therefore, the temperature will be 529.164 K.

5 0

2 years ago

Read 2 more answers