Answer:
The degrees of freedom are given by;

The significance level is 0.1 so then the critical value would be given by:

If the calculated value is higher than this value we can reject the null hypothesis that the arrivals are uniformly distributed over weekdays
Step-by-step explanation:
For this case we have the following observed values:
Mon 25 Tue 22 Wed 19 Thu 18 Fri 16 Total 100
For this case the expected values for each day are assumed:

The statsitic would be given by:

Where O represent the observed values and E the expected values
The degrees of freedom are given by;

The significance level is 0.1 so then the critical value would be given by:

If the calculated value is higher than this value we can reject the null hypothesis that the arrivals are uniformly distributed over weekdays
Step-by-step explanation:

I hope it makes sense
:)
Are there any choices that i can help with to solve the work problem
Answer:
See below.
Step-by-step explanation:
7 ) 29.0
= 4 1/7
= 4.142857142857.........
The 142857 repeats itself without bounds.
Answer:
11y-2x= -90
Step-by-step explanation:
for the point (1,-8)
x=1 and y= -8
for the equation,
2x -4y= -11
x= -1/m
m= -1/x
x = -1/ (-11/2 )
m= 2/11
so for the equation,
y-y1= m(x- x1)
y- -8=2/11(x-1)
11(y+8)= 2(x-1)
11y +88= 2x-2
11y-2x= -90